We will keep fighting for all libraries - stand with us!

Internet Archive Audio

eureka math grade 4 lesson 2 homework 4.2

  • This Just In
  • Grateful Dead
  • Old Time Radio
  • 78 RPMs and Cylinder Recordings
  • Audio Books & Poetry
  • Computers, Technology and Science
  • Music, Arts & Culture
  • News & Public Affairs
  • Spirituality & Religion
  • Radio News Archive

eureka math grade 4 lesson 2 homework 4.2

  • Flickr Commons
  • Occupy Wall Street Flickr
  • NASA Images
  • Solar System Collection
  • Ames Research Center

eureka math grade 4 lesson 2 homework 4.2

  • All Software
  • Old School Emulation
  • MS-DOS Games
  • Historical Software
  • Classic PC Games
  • Software Library
  • Kodi Archive and Support File
  • Vintage Software
  • CD-ROM Software
  • CD-ROM Software Library
  • Software Sites
  • Tucows Software Library
  • Shareware CD-ROMs
  • Software Capsules Compilation
  • CD-ROM Images
  • ZX Spectrum
  • DOOM Level CD

eureka math grade 4 lesson 2 homework 4.2

  • Smithsonian Libraries
  • FEDLINK (US)
  • Lincoln Collection
  • American Libraries
  • Canadian Libraries
  • Universal Library
  • Project Gutenberg
  • Children's Library
  • Biodiversity Heritage Library
  • Books by Language
  • Additional Collections

eureka math grade 4 lesson 2 homework 4.2

  • Prelinger Archives
  • Democracy Now!
  • Occupy Wall Street
  • TV NSA Clip Library
  • Animation & Cartoons
  • Arts & Music
  • Computers & Technology
  • Cultural & Academic Films
  • Ephemeral Films
  • Sports Videos
  • Videogame Videos
  • Youth Media

Search the history of over 866 billion web pages on the Internet.

Mobile Apps

  • Wayback Machine (iOS)
  • Wayback Machine (Android)

Browser Extensions

Archive-it subscription.

  • Explore the Collections
  • Build Collections

Save Page Now

Capture a web page as it appears now for use as a trusted citation in the future.

Please enter a valid web address

  • Donate Donate icon An illustration of a heart shape

Eureka math. Grade 4

Bookreader item preview, share or embed this item, flag this item for.

  • Graphic Violence
  • Explicit Sexual Content
  • Hate Speech
  • Misinformation/Disinformation
  • Marketing/Phishing/Advertising
  • Misleading/Inaccurate/Missing Metadata

[WorldCat (this item)]

plus-circle Add Review comment Reviews

599 Previews

10 Favorites

Better World Books

DOWNLOAD OPTIONS

No suitable files to display here.

PDF access not available for this item.

IN COLLECTIONS

Uploaded by station61.cebu on October 31, 2020

SIMILAR ITEMS (based on metadata)

  • Texas Go Math
  • Big Ideas Math
  • Engageny Math
  • McGraw Hill My Math
  • enVision Math
  • 180 Days of Math
  • Math in Focus Answer Key
  • Math Expressions Answer Key
  • Privacy Policy

CCSS Math Answers

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key

Engage ny eureka math 4th grade module 2 lesson 1 answer key, eureka math grade 4 module 2 lesson 1 problem set answer key.

Question 1. Convert the measurements. a. 1 km = _______1000________ m b. 4 km = _______4000________ m c. 7 km = ________7000_______ m d. ___18_______ km = 18,000 m e. 1 m = _______100________ cm f. 3 m = _______300________ cm g. 80 m = ______8000_________ cm h. ____120____ m = 12,000 cm

a. 1 km = 1000 m,

Explanation: 1 km is equal to 10 3 meter, 1 km = 1 X 10 X 10 X 10 = 1000 meter, So 1 km = 1000 m.

b. 4 km = 4000 m,

Explanation: 4 km is equal to 4 X 10 3 meter, 4 km = 4 X 10 X 10 X 10 = 4000 meter, So 1 km = 4000 m.

c. 7 km = 7000 m,

Explanation: 7 km is equal to 7 X 10 3 meter, 7 km = 7 X 10 X 10 X 10 = 7000 meter, So 7 km = 7000 m.

d. 18 km = 18000 m,

Explanation: 18 km is equal to 18 X 10 3 meter, 18 km = 18 X 10 X 10 X 10 = 18000 meter, So 18 km = 18000 m.

e. 1 m = 100cm,

Explanation: 1 m is equal to 10 2 centimeter, 1 m = 1 X 10 X 10 = 100 centimeter, So 1 m = 100 cm.

f. 3 m = 300cm,

Explanation: 3 m is equal to 3 X 10 2 centimeter, 3 m = 3 X 10 X 10 = 100 centimeter, So 3 m = 300 cm.

g. 80 m = 8000 cm,

Explanation: 80 m is equal to  80 X 10 2 centimeter, 80 m = 80 X 10 X 10 = 8000 centimeter, So 80 m = 8000 cm.

h. 120 m = 12,000 cm,

Explanation: 120 m is equal to 120 X 10 2 centimeter, 120 m = 120 X 10 X 10 = 12,000 centimeter, So 120 m = 12,000 cm.

Question 2. Convert the measurements. a. 3 km 312 m = _____3,312__________ m b. 13 km 27 m = ______13,027_________ m c. 915 km 8 m = _______9,15,008________ m d. 3 m 56 cm = ________3,56_______ cm e. 14 m 8 cm = _________1,408______ cm f. 120 m 46 cm = _______12,046________ cm

a. 3 km 312 m = 3,312 m,

Explanation: As we know 1 km is equal to 10 3 meter, So 3 km 312 m = 3 X 10 3 + 312 = 3,312 meter, Therefore 3 km 312 m = 3,312 m.

b. 13 km 27 m = 13,027 m,

Explanation: As we know 1 km is equal to 10 3 meter, So 13 km 27 m = 13 X 10 3 + 27 = 13,027 meter, Therefore 13 km 27 m = 13,027 m.

c. 915 km 8 m = 9,15,008 m,

Explanation: As we know 1 km is equal to 10 3 meter, So 915 km 8 m = 915 X 10 3 + 8 = 9,15,008 meter, Therefore 915 km 8 m = 9,15,007 m.

d. 3 m 56 cm = 356 cm

Explanation: As we know 1 m is equal to 10 2 centimeter, 3 m 56 cm = 3 X 10 2 + 56 = 300 + 56 = 3,56 centimeter, So 3 m 56 cm = 3,56 cm.

e.  14 m 8 cm = 1,408 cm,

Explanation: As we know 1 m is equal to 10 2 centimeter, 14 m 8 cm = 14 X 10 2 + 8 = 1400 + 8 = 1,408 centimeter, So 14 m 8 cm = 1,408 cm.

f. 120 m 46 cm = 12,046 cm,

Explanation: As we know 1 m is equal to 10 2 centimeter, 120 m 46 cm = 120 X 10 2 + 46 = 12000 + 46 = 12,046 centimeter, So 120 m 46 cm = 12,046 cm.

Question 3. Solve. a. 4 km − 280 m b. 1 m 15 cm – 34 cm c. Express your answer in the smaller unit: 1 km 431 m + 13 km 169 m d. Express your answer in the smaller unit: 231 m 31 cm − 14 m 48 cm e. 67 km 230 m + 11 km 879 m f. 67 km 230 m − 11 km 879 m

Use a tape diagram to model each problem. Solve using a simplifying strategy or an algorithm, and write your answer as a statement.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-1

Explanation: Given 4 km − 280 m as 4 km = 4 X 10 3 m = 4,000 m, Used a tape diagram to model 4 km – 280 m = 3,720 m as shown above in the picture, so 4000 m      -280 m      3,720 m Statement is 4 kilometers minus 280 meters is equal to 3,720 meters.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-2

Explanation: Given 1 m 15 cm − 34 cm as 1 m 15 cm = 1 X 10 2 + 15 = 100 + 15 = 115 cm, Used a tape diagram to model 115 cm – 34 cm = 81 cm as shown above in the picture, so 115 cm      – 34 cm         81 cm Statement is 1 meter 15 centimeters minus 34 centimeters is equal to 81 centimeters.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-3

Explanation: Given 1 km 431 m + 13 km 169 m as 1 km 431 m = 1 X 10 3 + 431 = 1000 + 431 = 1,431 m and 13 km 169 m = 13 X 10 3 + 169 =13,169 m Used a tape diagram to model 1431 m + 13169 m = 14,600 m as shown above in the picture, 001431 m +13169 m 14,600 m Now 14,600 m in the smaller unit in millimeter is as 1 meter is equal to 1000 millimeter, So 14,600 X 1000 = 14,600,000 millimeters. Statement : 1 kilometer and 431 meters plus 13 kilometers 169 meters gives 14,600,000 millimeters.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-4

Explanation: Given 231 m 31 cm – 14 m 48 cm as 231 m 31 cm = 231 X 10 2 + 31 = 23100 + 31 = 23,131 cm and 14 m 48 cm = 14 X 10 2 + 48 =1,448 cm Used a tape diagram to model 23,131 cm – 1,448 cm = 21,683 cm as shown above in the picture, 23134 cm – 1448 cm 21,683 cm Now 21,683 cm in the smaller unit millimeters is as 1 centimeter is equal to 10 millimeter, So 21,683 X 10 = 216,830 millimeters. Statement : 231 meter and 31 centimeters minus 14 meters 48 centimeters gives 216,830 millimeters.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-5

67 kilometer and 230 meters plus 11 kilometers and 879 meters is 79,109 meters,

Explanation: Given 67 km 230 m + 11 km 879 m as 67 km 230 m = 67 X 10 3 + 230 = 67000 + 230 = 67,230 m and 11 km 879 m = 11 X 10 3 + 879 =11,879 m Used a tape diagram to model 67230 m + 11879 m = 79,109 m as shown above in the picture, 67230 m +11879 m 79,109 m So  67 km 230 m + 11 km 879 m = 79,109 m, Statement : 67 kilometer and 230 meters plus 11 kilometers and 879 meters is 79,109 meters.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-6

Explanation: Given 67 km 230 m – 11 km 879 m as 67 km 230 m = 67 X 10 3 + 230 = 67000 + 230 = 67,230 m and 11 km 879 m = 11 X 10 3 + 879 =11,879 m Used a tape diagram to model 67230 m – 11879 m = 55,351 m as shown above in the picture, 67230 m -11879 m 55,351 m So  67 km 230 m – 11 km 879 m = 55,351 m, Statement : 67 kilometer and 230 meters minus 11 kilometers and 879 meters is 55,351 meters.

Question 4. The length of Carter’s driveway is 12 m 38 cm. His neighbor’s driveway is 4 m 99 cm longer. How long is his neighbor’s driveway?

Answer: Neighbor’s drive is 17 m 37 cm or 1737 cm,

Explanation: Given The length of Carter’s driveway is 12 m 38 cm and his neighbor’s driveway is 4 m 99 cm longer. So neighbor’s drive is 12 m 38 cm plus 4 m 99 cm we know  1 m is equal to 10 2 centimeter, 12 m 38 cm = 12 X 10 2 + 38 = 1238 cm and 4 m 99 cm = 4 X 10 2 + 99 = 499 cm, now 1238 cm + 499 cm = 1238 cm +499 cm 1737 cm Therefore, Neighbor’s drive is 17 m 37 cm or 1737 cm.

Question 5. Enya walked 2 km 309 m from school to the store. Then, she walked from the store to her home. If she walked a total of 5 km, how far was it from the store to her home?

Answer: It is 2691 m from the store to her home,

Explanation: Given Enya walked 2 km 309 m from school to the store. Then, she walked from the store to her home. If she walked a total of 5 km, it is 5 km – 2 km 309m from the store to her home, So 5 km means 5 X 10 3  – (2 X 10 3 + 309) = 5000 m – 2309 m = 5000 m -2309 m 2691 m Therefore, It is 2691 m from the store to her home.

Question 6. Rachael has a rope 5 m 32 cm long that she cut into two pieces. One piece is 249 cm long. How many centimeters long is the other piece of rope?

Answer: The other piece of rope 283 cm long,

Explanation: Given Rachael has a rope 5 m 32 cm long that she cut into two pieces and one piece is 249 cm long. The other piece of rope is 5 m 32 cm minus 249 cm long, So, 5 m 32 cm – 249 cm = 5 X 10 2 + 32 – 249 = 532 – 249 = 283 cm, therefore, the other piece of rope 283 cm long.

Question 7. Jason rode his bike 529 fewer meters than Allison. Jason rode 1 km 850 m. How many meters did Allison ride?

Allison rode 2 km 379 meters or 2379 meters,

Explanation: Given Jason rode his bike 529 fewer meters than Allison. Jason rode 1 km 850 m. Number of meters Allison rode is 1 km 850 m + 529 m = 1 X 10 3 + 850 + 529 = 1850 + 529 = 2379 meters. Therefore Allison rode 2 km 379 meters or 2379 meters.

Eureka Math Grade 4 Module 2 Lesson 1 Exit Ticket Answer Key

Question 1. Complete the conversion table.

Explanation: 71 km is equal to 71 X  10 3 = 71 X 1000 = 71,000 m, so 71 km = 71,000 m.

30 km is equal to 30 X 10 3 = 30 X 1000 = 30,000 m, so 30 km = 30,000 m.

81 m is equal to 81 X 10 2 = 81 X 100 = 8,100 cm, so 81 m = 8,100 cm.

4 m is equal to 4 X 10 2 = 4 X 100 = 400 cm, so 4 m = 400 cm.

Question 2. 13 km 20 m = ____13020___ m Answer: 13 km 20 m = 13,020 m

Explanation: Given 13 km 20 m as 1 km is equal to 10 3 m so 13 km 20 m = 13 X 10 3 + 20 m = 13 X 1000 + 20 = 13000 + 20 = 13020, therefore 13 km 20 m = 13,020 m.

Question 3. 401 km 101 m – 34 km 153 m = _366,948 m or 366 km 948 m__ Answer: 401 km 101 m – 34 km 153 m = 366,948 m or 366 km 948 m,

Explanation: Given 401 km 101 m – 34 km 153 m as 401 km 101 m = 401 X 10 3 + 101 = 401000 + 101 = 401,101 m and 34 km 153 m = 34 X 10 3 + 153 = 34153 m Now 401,101 – 34,153 = 401101 m -34153 m 366,948 m So, 401 km 101 m – 34 km 153 m = 366,948 m or 366 km 948 m.

Question 4. Gabe built a toy tower that measured 1 m 78 cm. After building some more, he measured it, and it was 82 cm taller. How tall is his tower now? Draw a tape diagram to model this problem. Use a simplifying strategy or an algorithm to solve and write your answer as a statement.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-7

Explanation: Given Gabe built a toy tower that measured 1 m 78 cm. After building some more, he measured it, and it was 82 cm taller. So Gabe tower is 1 m 78 cm + 82 cm = 1 X 10 2 + 78 cm + 82 cm = 178 cm + 82 cm  = 178 cm + 82 cm 260 cm tall. Drawn a tape diagram to model this problem. Used a simplifying strategy to solve and wrote my statement as Gabe tower is 2 meter 60 centimeter tall or 260 centimeter tall.

Eureka Math Grade 4 Module 2 Lesson 1 Homework Answer Key

Question 1. Find the equivalent measures. a. 5 km = ______5,000_________ m b. 13 km = _____13,000__________ m c. _____17__________ km = 17,000 m d. 60 km = ______60,000_________ m e. 7 m = ________700_______ cm f. 19 m = _______1,900________ cm g. ______24_________ m = 2,400 cm h. 90 m = _____9,000______ cm

a. 5 km = 5000 m,

Explanation: 1 km is equal to 10 3 meter, 5 km = 5 X 10 X 10 X 10 = 5000 meter, So 5 km = 5000 m.

b. 13 km = 13,000 km,

Explanation: 1 km is equal to 10 3 meter, 13 km = 13 X 10 X 10 X 10 = 13000 meter, So 13 km = 13,000 m.

c. _______________ km = 17,000 m, 17 km = 17,000 m,

Explanation: 1 m is equal to 1 ÷ 10 3 km, 17,000 m = 17,000 ÷ 10 X 10 X 10 = 17000 ÷ 1000 = 17 km, So 17 km = 17,000 m.

d. 60 km = 60,000 m,

Explanation: 1 km is equal to 10 3 meter, 60 km = 60 X 10 X 10 X 10 = 60,000 meter, So 60 km = 60,000 m.

e. 7 m = 700 cm,

Explanation: 1 m is equal to 10 2 centimeter, 7 m = 7 X 10 X 10 = 700 centimeter, So 7 m = 700 centimeter.

f. 19 m = 1,900 cm,

Explanation: 1 m is equal to 10 2 centimeter, 19 m = 19 X 10 X 10 = 1,900 centimeter, So 19 m = 1,900 centimeter.

g. ____________ m = 2,400 cm,

Explanation: 1 cm is equal to 1 ÷ 10 2 m, 2,400 cm = 2,400 ÷ 10 X 10 = 2400 ÷ 100 = 24 m, So 24 m = 2,400 cm.

h. 90 m = 9,000 cm,

Explanation: 90 m is equal to 10 2 centimeter, 90 m = 90 X 10 X 10 = 9,000 centimeter, So 90 m = 9,000 centimeter.

Question 2. Find the equivalent measures. a. 7 km 123 m = _______7,123________ m b. 22 km 22 m = ______22,022_________ m c. 875 km 4 m = _______875,004________ m d. 7 m 45 cm = _______745________ cm e. 67 m 7 cm = ________6707_______ cm f. 204 m 89 cm = ____204,89__________ cm

a. 7 km 123 m = 7,123 m,

Explanation: 1 km is equal to 10 3 meter, 7 km 123 m = 7 X 10 X 10 X 10 + 123 = 7,000 + 123 = 7,123 meter, So, 7 km 123 m = 7,123 m.

b. 22 km 22 m = 22,022 m,

Explanation: 1 km is equal to 10 3 meter, 22 km 22 m = 22 X 10 X 10 X 10 + 22 = 22,000 + 22 = 22,022 meter, So, 22 km 22 m = 22,022 m.

c. 875 km 4 m = 875,004 m,

Explanation: 1 km is equal to 10 3 meter, 875 km 4 m = 875 X 10 X 10 X 10 + 4 = 875,000 + 4 = 875004 meter, So, 875 km 4 m = 875,004 m.

d. 7 m 45 cm =745 cm,

Explanation: 1 m is equal to 10 2 meter, 7 m 45 cm =  7 X 10 X 10 + 45 = 745 cm, So, 7 m 45 cm =745 cm.

e. 67 m 7 cm = 6,707 cm,

Explanation: 1 m is equal to 10 2 meter, 67 m 7 cm =  67 X 10 X 10 + 7 = 6700 + 7 = 6,707 cm, So, 67 m 7 cm = 6,707 cm.

f. 204 m 89 cm = 204,89 cm,

Explanation: 1 m is equal to 10 2 meter, 204 m 89 cm =  204 X 10 X 10 + 89 = 20400 + 89 = 204,89 cm, So, 204 m 89 cm = 204,89 cm.

Question 3. Solve. a. 2 km 303 m – 556 m b. 2 m – 54 cm c. Express your answer in the smaller unit: 338 km 853 m + 62 km 71 m d. Express your answer in the smaller unit: 800 m 35 cm – 154 m 49 cm e. 701 km – 523 km 445 m f. 231 km 811 m + 485 km 829 m

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-8

Explanation: Given 2 km 303 m − 556 m as 2 km 303 m = 2 X 10 3 m + 303 m = 2,303 m, Used a tape diagram to model 2,303 m  – 556 m = 1,747 m as shown above in the picture, 2303 m – 556 m   1,747 m Statement is 2 kilometers 303 m minus 556 meters is equal to 1,747 meters.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-9

Explanation: Given 2 m − 54 cm as 2 m =  2 X 10 2 cm so 200 cm – 54 cm = 146 cm, Used a tape diagram to model 200 cm  – 54 cm = 146 cm as shown above in the picture, 200 cm    –  54 cm       146 cm Statement is 2 meters minus 54 centimeters is equal to 146 centimeters.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-10

Explanation: Given 338 km 853 m + 62 km 71 m as 338 km 853 m = 338 X 10 3 + 853 = 338000 + 853 = 338853 m and 62 km 71 m = 62 X 10 3 + 71 =62000 + 71 m = 62071 m Used a tape diagram to model 338853 m + 62071 m = 400,924 m as shown above in the picture, 338853 m +62071 m 400,924 m Now 400,924 m in the smaller unit in millimeter is as 1 meter is equal to 1000 millimeter, So 400,924 X 1000 = 400,924,000 millimeters. Statement : 338 kilometer and 853 meters plus 62 kilometers and 71 meters is 400,924 meters or 400,924,000 millimeters,

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-11

Explanation: Given 800 m 35 cm – 154 m 49 cm as 800 m 35 cm = 800 X 10 2 + 35 = 80000 + 35 = 80,035 cm and 154 m 49 cm = 154 X 10 2 + 49 =15,449 cm Used a tape diagram to model 80,035 cm – 15,449 cm = 64,586 cm as shown above in the picture, 80,035 cm – 15449 cm 64,586 cm Now 64,586 cm in the smaller unit millimeters is as 1 centimeter is equal to 10 millimeter, So 64,586 X 10 = 645,860 millimeters. Statement :  800 meter and 35 centimeters minus 154 meters 49 centimeters gives 64,586 cm or 645,860 millimeters.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-12

701 kilometers minus 523 kilometers 445 meters is equal to 177,555 meters,

Explanation: Given 701 km − 523 km 445 m, 701 km = 701 X 10 3 m = 701000 m, and 523 km 445 m = 523 X 10 3 m + 445 m = 523445 m Used a tape diagram to model 701000 m  – 523445 m = 177,555 m as shown above in the picture, 701000 m -523445 m   177,555 m Statement is 701 kilometers minus 523 kilometers 445 meters is equal to 177,555 meters.

Eureka Math Grade 4 Module 2 Lesson 1 Answer Key-13

Explanation: Given 231 km 811 m + 485 km 829 m, 231 km 811 m = 231 X 10 3 m =231000 m + 811 m = 231811m and 485 km 829 m = 485 X 10 3 m + 829 m = 485829 m Used a tape diagram to model 231811 m + 485829 m = 717640 m as shown above in the picture, 231811 m +485829 m    717640 m Statement is 231 kilometers 811 meters plus 485 kilometers 829 meters is equal to 717,640 meters,

Question 4. The length of Celia’s garden is 15 m 24 cm. The length of her friend’s garden is 2 m 98 cm more than Celia’s. What is the length of her friend’s garden?

Answer: The length of Celia’s friend garden is 1822 cm or 18 m 22 cm,

Explanation: Given the length of Celia’s garden is 15 m 24 cm, the length of her friend’s garden is 2 m 98 cm more than Celia’s. So the length of her friend’s garden is 15 m 24 cm + 2 m 98 cm = 1 m = 10 2 cm, 15 m 24 cm = 15 X 10 2 + 24 cm = 1500 + 24 = 1524 cm and 2 m 98 cm = 2 X 10 2 + 98 cm = 200 + 98 = 298 cm, Now 1524 cm + 298 cm = 1524 cm +298 cm 1822 cm Therefore, the length of Celia’s friend garden is 1822 cm or 18 m 22 cm.

Question 5. Sylvia ran 3 km 290 m in the morning. Then, she ran some more in the evening. If she ran a total of 10 km, how far did Sylvia run in the evening?

Answer: Sylvia ran 6 km 710 m or 6710 m in the evening,

Explanation: Sylvia ran 3 km 290 m in the morning. Then, she ran some more in the evening. If she ran a total of 10 km, So Sylvia ran in the evening is 10 km – 3 km 290 m = as 1 km = 10 3 m so 10 km = 10000 m and 3 km 290 m = 3 X 10 3 m + 290 m =3290 m 10000 m -3290 m  6710 m Therefore, Sylvia ran 6 km 710 m or 6710 m in the evening.

Question 6. Jenny’s sprinting distance was 356 meters shorter than Tyler’s. Tyler sprinted a distance of 1 km 3 m. How many meters did Jenny sprint?

Answer: Jenny sprint distance is 647 m,

Explanation: Given Jenny’s sprinting distance was 356 meters shorter than Tyler’s. Tyler sprinted a distance of 1 km 3 m. So number of meters did Jenny sprint is 1 km 3 m – 356 m = 1 km = 10 3 m so 1 km 3 m = 1 X 10 3 m +3 m = 1000 + 3 = 1003 m, Now 1003 m – 356 m 1003 m -356 m 647 m Therefore, Jenny sprint distance is 647 m.

Question 7. The electrician had 7 m 23 cm of electrical wire. He used 551 cm for one wiring project. How many centimeters of wire does he have left?

Answer: The electrician is left with 172 cm electrical wire,

Explanation: Given the electrician had 7 m 23 cm of electrical wire. He used 551 cm for one wiring project. So number of centimeters of wire left is 7 m 23 cm – 551 cm = as 1 m = 10 2 cm So 7 m 23 cm = 7 X 10 2 + 23 = 700 + 23 = 723 cm – 551 cm = 723 cm -551 cm 172 cm Therefore, the electrician is left with 172 cm electrical wire.

Eureka Math Grade 4 Module 2 Answer Key

Leave a comment cancel reply.

You must be logged in to post a comment.

IMAGES

  1. EngageNY (Eureka Math) Grade 4 Module 2 Answer Key by MathVillage

    eureka math grade 4 lesson 2 homework 4.2

  2. EngageNY (Eureka Math) Grade 4 Module 2 Answer Key by MathVillage

    eureka math grade 4 lesson 2 homework 4.2

  3. Eureka Math Homework Helpers Grade 4 : See a Problem?

    eureka math grade 4 lesson 2 homework 4.2

  4. Eureka Math Homework Helpers Grade 4

    eureka math grade 4 lesson 2 homework 4.2

  5. My Eureka Math // Grade 4 Module 2 Lesson 2 Test Preparation

    eureka math grade 4 lesson 2 homework 4.2

  6. Eureka Math Grade 4 Module 3 Lesson 2 and 3 Practice Problems by sarah

    eureka math grade 4 lesson 2 homework 4.2

VIDEO

  1. Eureka math grade 5 module 2 lesson 19 homework

  2. Eureka math grade 5 module 3 lesson 2 homework

  3. Eureka math grade 5 module 2 lesson 28 homework

  4. Eureka math grade 4 module 3 lesson 6

  5. Eureka Math Module 5 Lesson 4 Homework

  6. 7th Grade Eureka Math: Module 2, Lesson 1

COMMENTS

  1. Eureka Math Homework Time Grade 4 Module 4 Lesson 2

    It's Homework Time! Help for fourth graders with Eureka Math Module 4 Lesson 2.

  2. Eureka Math Grade 4 Module 4 Lesson 2 Answer Key

    Eureka Math Grade 4 Module 4 Lesson 2 Template Answer Key. In the above image, the acute angles will be <D, <F. In the above image, the right angles will be <A, <B, <E, <G. In the above image, the obtuse angles will be <C, <H, <I, <J. Acute angle: An acute angle is an angle that measures less than 90 degrees.

  3. Eureka Math Grade 4 Module 2 Lesson 4 Answer Key

    Engage NY Eureka Math 4th Grade Module 2 Lesson 4 Answer Key Eureka Math Grade 4 Module 2 Lesson 4 Pattern Sheet Answer Key. Write in meters and centimeters. Question 1. 3 m + 1 m = 4 m 0 cm, Explanation: Given 3 m + 1 m adding 3 m to 1 m we get 4 m and 0 cm as 3 m 0 cm +1 m 0 cm 4 m 0 cm. Question 2. 4 m + 2 m = 6 m 0 cm, Explanation:

  4. EngageNY Grade 4 Module 4 Lesson 2

    EngageNY/Eureka Math Grade 4 Module 4 Lesson 2For more videos, please visit http://bit.ly/engageportalPLEASE leave a message if a video has a technical diffi...

  5. PDF Grade 4 • Module 4

    GRADE Mathematics Curriculum GRADE 4 • MODULE 4 Module 4: Angle Measure and Plane Figures Answer Key ... 2 Lesson 4 Answer Key 4• Homework 1. Parallel lines accurately traced 2. Answers will vary. ... 4 2. 90° 3. 1 360 4. Answers will vary. Homework 1. a. 60° b. 130° c. 315° d. 120°

  6. PDF Grade 4, Module 4 Student File A

    10 9 8 7 6 5 4 3 2 1 Eureka Math™ Grade 4, Module 4 Student File_A Contains copy-ready classwork and homework ... 42 HomeworkLesson 4 Name Date 1. Use the right angle template that you made in class to determine if each of the following angles is greater than, less than, or equal to a right angle. ...

  7. PDF Eureka Math Homework Helper 2015-2016 Grade 4

    Grade 4 Module 2 Lessons 1-5 Eureka Math™ Homework Helper 2015-2016. 2015-16 4•2 Homework Helper Lesson 1 : Express metric length measurements in terms of a smaller unit; model and solve addition and subtraction word problems involving metric length. G4-M2-Lesson 1 1. Find the equivalent measures.

  8. Course: G4M2: Unit Conversions and Problem Solving with Metric Measurement

    Unit Conversions and Problem Solving with Metric Measurement. Eureka Essentials: Grade 4. An outline of learning goals, key ideas, pacing suggestions, and more! Fluency Games. Teach Eureka Lesson Breakdown. Downloadable Resources. Teacher editions, student materials, application problems, sprints, etc. Application Problems.

  9. 4th Grade Math (Eureka Math/EngageNY)

    4th grade (Eureka Math/EngageNY) 7 units · 152 skills. Unit 1 Module 1: Place value, rounding, and algorithms for addition and subtraction. Unit 2 Module 2: Unit conversions and problem solving with metric measurement. Unit 3 Module 3: Multi-digit multiplication and division. Unit 4 Module 4: Angle measure and plane figures.

  10. PDF Grade 4, Module 6 Student File A

    10 9 8 7 6 5 4 3 2 1 Eureka Math™ Grade 4, Module 6 Student File_A Contains copy-ready classwork and homework A Story of ... = 2 + 0.4 = 2.4 A STORY OF UNITS ©2015 Great Minds. eureka-math.org 7 G4-M6-SE-1.3.1-11.2015. Lesson 2 Homework 4 ...

  11. Eureka Math Grade 4 Module 5 Lesson 2 Answer Key

    4/7 = 1 /7 + 2/7 + 1/7. 4/7 = 1/7 + 1/7 + 2/7. Eureka Math Grade 4 Module 5 Lesson 2 Homework Answer Key. Question 1. Step 1: Draw and shade a tape diagram of the given fraction. Step 2: Record the decomposition as a sum of unit fractions. Step 3: Record the decomposition of the fraction two more ways. (The first one has been done for you.)

  12. Eureka Math Homework Time Grade 4 Module 2 Lesson 4

    It's Homework Time! Help for fourth graders with Eureka Math Module 2 Lesson 4.

  13. PDF Eureka Math 2nd Module 1 TE (2)

    ./!+01!,&.,2)-& & *3&4,14,-,)+2+0*) 5& "#$%!&'%!(%)%#*%)!+,!*%-./%01! %#$.2*34%!,&20%#&,!5'.!#%%0!,266.*&! &.!/+,237+8%!&'%!9%30,!:&%# ;<*3-%,!.*!= ; 4*.26,>1!.*!42+0 ...

  14. PDF Eureka Math

    Eureka Math™ Grade 4 Module 1 Student File_A Student Workbook This file contains: ... 2 ©2015 Great Minds. eureka-math.org Lesson 1: Interpret a multiplication equation as a comparison. Lesson 1 Problem Set 4. Jane saved $800. ... Lesson 2 Homework Name Date 1. As you did during the lesson, label and represent the product or quotient by ...

  15. Eureka math. Grade 4 : Free Download, Borrow, and Streaming : Internet

    Eureka math. Grade 4. Eureka helps students to truly understand math, connect it to the real world, and prepare them to solve problems they haven't encountered before. The team of teachers and mathematicians who created Eureka Math believe that it is not enough for students to know the process for solving a problem; they need to know why that ...

  16. Eureka Math Grade 4 Module 2 Lesson 2 Answer Key

    Engage NY Eureka Math 4th Grade Module 2 Lesson 2 Answer Key Eureka Math Grade 4 Module 2 Lesson 2 Problem Set Answer Key Question 1. Complete the conversion table. Mass kg g 1 1,000 ... Eureka Math Grade 4 Module 2 Lesson 2 Homework Answer Key. Question 1. Complete the conversion table. Mass. kg: g. 1. 1,000: 6. 6,000: 8. 8,000: 15: 15000. 24: ...

  17. Eureka Math Grade 4 Module 3 Lesson 2 Answer Key

    Given wide as 4 feet and long is 12 feet, So perimeter of the blanket is 2 × (12 feet + 4 feet) = 2 × (16 feet) = 32 feet and area is 12 feet × 4 feet = 48 square feet. Eureka Math Grade 4 Module 3 Lesson 2 Homework Answer Key. Question 1. A rectangular pool is 7 feet wide. It is 3 times as long as it is wide. a.

  18. Eureka Math Grade 4 Module 1 Lesson 2

    EngageNY/Eureka Math Grade 4 Module 1 Lesson 2For more Eureka Math (EngageNY) videos and other resources, please visit http://EMBARC.onlinePLEASE leave a mes...

  19. Eureka Math Homework Time Grade 4 Module 4 Lesson 4

    It's Homework Time! Help for fourth graders with Eureka Math Module 4 Lesson 4.

  20. Eureka Math Grade 2 Module 4 Lesson 4 Answer Key

    Eureka Math Grade 2 Module 4 Lesson 4 Exit Ticket Answer Key. Question 1. Solve. Draw a tape diagram or number bond to add or subtract tens. Write the new number sentence. ... Eureka Math Grade 2 Module 4 Lesson 4 Homework Answer Key. Question 1. Solve. Draw and label a tape diagram to subtract 10, 20, 30, 40, etc.

  21. EngageNY Grade 5 Module 4 Lesson 2 (updated)

    EngageNY/Eureka Math Grade 5 Module 4 Lesson 2 (updated)For more videos, please visit http://bit.ly/engageportal

  22. Eureka Math Grade 4 Module 2 Lesson 1 Answer Key

    Solve using a simplifying strategy or an algorithm, and write your answer as a statement. a. 4 km − 280 m. 4 km - 280 m = 3,720 m. Answer: 4 kilometers minus 280 meters is equal to 3,720 meters, Explanation: Given 4 km − 280 m as. 4 km = 4 X 10 3 m = 4,000 m, Used a tape diagram to model 4 km - 280 m = 3,720 m.

  23. Eureka Math Grade 2 Module 1 Lesson 4

    EngageNY/Eureka Math Grade 2 Module 1 Lesson 4For more videos, please visit http://bit.ly/engageportalPLEASE leave a message if a video has a technical diffi...