assignment 5 design a ringtone code

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iRubric: Unit 5: EarSketch:Build a Ringtone rubric

Assignment 5 design a ringtone code

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One major element of the content is the Code-Along videos. Unit 5: Programming in EarSketch ... Assignment: Design a Ringtone in EarSketch. Syllabus. edhesive introtocs syllabus ?id=

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Answer to Question #143345 in Python for Larry

Print(10<5)

"10<5" is false.

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Assignment 5: Design a Ringtone For this assignment, you will code a ringtone in EarSketch that incorporates the following Python commands: You must use both of the EarSketch functions fitMedia() and setEffect() for an effect in your ringtone (such as a fade or distortion). You must use string operations (concatenation or splicing) to create your own beat, using the EarSketch function makeBeat(). You must use for loops to add repetition to your ringtone. You must use at least one user-defined (custom) function to create musical sections for your ringtone. In addition to the required coding components above, your ringtone must also meet the following general requirements: Your ringtone should be a minimum of 60 seconds and a maximum of 90 seconds (average length of a phone's ring). Your ringtone should include a sound clip from Ciara or Common, found in the EarSketch sound library. Your ringtone should appeal to high school students. Your ringtone should use efficient code whenever possible (for example, using a for loop to repeat a section of music instead of writing the code for that section a second time), as most phones have only a small amount of memory available for ringtone downloads.

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Answer to Assignment 5: Design a Ringtone on Earsketch from Edhesive

Independent variable: the best method to get rid of them.

Dependent variable: washing with soap and water.

Hypothesis: Organic oils

Control group: water

Step-by-step explanation:

D. Heat each cube to the same temperature, place each cube into different containers with 500 grams of water at the same temperature, and measure the temperature of the water.

To solve this problem, we can use the conservation of energy and conservation of momentum principles.

Conservation of energy:

The total initial energy is the rest energy of the proton and neutron, which is given by:

Ei = (mp + mn)c^2

where mp and mn are the masses of the proton and neutron, respectively, and c is the speed of light.

The total final energy is the rest energy of the deuteron plus the energy of the gamma ray, which is given by:

Ef = (md)c^2 + Eg

where md is the mass of the deuteron and Eg is the energy of the gamma ray.

According to the conservation of energy principle, the initial energy and final energy must be equal, so we have:

(mp + mn)c^2 = (md)c^2 + Eg

Conservation of momentum:

The total initial momentum is zero because the proton and neutron are at rest. The total final momentum is the momentum of the deuteron and the momentum of the gamma ray. Since the gamma ray is massless, its momentum is given by:

where pg is the momentum of the gamma ray.

According to the conservation of momentum principle, the total final momentum must be equal to zero, so we have:

0 = pd + pg

where pd is the momentum of the deuteron.

Solving for md and pd:

From the conservation of energy equation, we can solve for md:

md = (mp + mn - Eg/c^2)/c^2

Substituting this expression into the conservation of momentum equation, we get:

pd = -pg = -Eg/c

Substituting the given values, we have:

mp = 1.6726 × 10^-27 kg mn = 1.6749 × 10^-27 kg Eg = 2.2 × 10^6 eV = 3.52 × 10^-13 J

Using c = 2.998 × 10^8 m/s, we get:

md = (1.6726 × 10^-27 kg + 1.6749 × 10^-27 kg - 3.52 × 10^-13 J/(2.998 × 10^8 m/s)^2)/(2.998 × 10^8 m/s)^2 = 3.3435 × 10^-27 kg

pd = -Eg/c = -(3.52 × 10^-13 J)/(2.998 × 10^8 m/s) = -1.1723 × 10^-21 kg·m/s

Therefore, the mass of the deuteron is 3.3435 × 10^-27 kg, and its momentum is -1.1723 × 10^-21 kg·m/s.

Time taken by the tomatoes to each the ground

using h = 1/2 g t^2 

t^2 = 2h/g = 2 x 50/ 9.8 = 10.2

t = 3.2 sec 

horizontal ditance = speed x time = 3 x 3.2 = 9.6 meters

The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02

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