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Eureka Math Grade 5 Module 4 Lesson 29 Answer Key

Engage ny eureka math 5th grade module 4 lesson 29 answer key, eureka math grade 5 module 4 lesson 29 problem set answer key.

Question 1. Divide. Rewrite each expression as a division sentence with a fraction divisor, and fill in the blanks. The first one is done for you.

Example: 2 ÷ 0.1 = 2 ÷ \(\frac{1}{10}\) = 20 There are 10 tenths in 1 whole. There are 20 tenths in 2 wholes.

a. 5 ÷ 0.1 There are ____ tenths in 1 whole. There are ____ tenths in 5 wholes.

Answer: There are 10 tenths in 1 whole. There are 50 tenths in 5 wholes.

Explanation: Given that 5 ÷ 0.1 which is 50. In that, there are 10 tenths in 1 whole and there are 50 tenths in 5 wholes.

There are ____ tenths in 1 whole. There are ____ tenths in 8 wholes.

Answer: There are 10 tenths in 1 whole. There are 8 tenths in 5 wholes.

Explanation: Given that 8 ÷ 0.1 which is 80. In that, there are 10 tenths in 1 whole and there are 80 tenths in 8 wholes.

c. 5.2 ÷ 0.1

There are tenths in 5 wholes. There are ____ tenths in 2 tenths. There are ____ tenths in 5.2.

Answer: There are 2 tenths in 2 tenths. There are 52 tenths in 5.2.

d. 8.7 ÷ 0.1 There are ____ tenths in 8 wholes. There are ____ tenths in 7 tenths. There are ____ tenths in 8.7.

Answer: There are 80 tenths in 8 wholes. There are 7 tenths in 7 tenths. There are 87 tenths in 8.7.

Explanation: Given that 8.7 ÷ 0.1 which is 87. In that, there are 80 tenths in 8 whole and there are 7 tenths in 7 tenths and there are 87 tenths in 8.7.

e. 5 ÷ 0.01 There are 100 hundredths in 1 whole. There are 500 hundredths in 5 wholes.

Answer: There are ____ hundredths in 1 whole. There are ____ hundredths in 5 wholes.

Explanation: Given that 5 ÷ 0.01 which is 500. In that, there are 100 hundredths in 1 whole and there are 500 hundredths in 5 wholes.

f. 8 ÷ 0.01 There are ____ hundredths in 1 whole. There are ____ hundredths in 8 wholes.

Answer: There are 100 hundredths in 1 whole. There are 800 hundredths in 8 wholes.

Explanation: Given that 8 ÷ 0.01 which is 800. In that, there are 100 hundredths in 1 whole and there are 800 hundredths in 8 wholes.

g. 5.2 ÷ 0.01 There are ____ hundredths in 5 wholes. There are ____ hundredths in 2 tenths. There are ____ hundredths in 5.2.

Answer: There are 500 hundredths in 1 whole. There are 20 hundredths in 5 tenths. There are 520 hundredths in 5.2.

Explanation: Given that 5.2 ÷ 0.01 which is 520. In that, there are 500 hundredths in 1 whole and there are 20 hundredths in 5 tenths and there are 520 hundredths in 5.2.

h. 8.7 ÷ 0.01 There are ____ hundredths in 8 wholes. There are ____ hundredths in 7 tenths. There are ____ hundredths in 8.7.

Answer: There are 800 hundredths in 8 whole. There are 70 hundredths in 7 tenths. There are 870 hundredths in 8.7.

Explanation: Given that 8.7 ÷ 0.01 which is 870. In that, there are 800 hundredths in 8 whole and there are 70 hundredths in 7 tenths and there are 870 hundredths in 8.7.

Question 2. Divide. a. 6 ÷ 0.1

Answer: 6 ÷ 0.1 = 60.

Explanation: The division of 6 ÷ 0.1 is 60.

b. 18 ÷ 0.1

Answer: 18 ÷ 0.1 = 180.

Explanation: The division of 18 ÷ 0.1 is 180.

c. 6 ÷ 0.01

Answer: 6 ÷ 0.01 = 600.

Explanation: The division of 6 ÷ 0.01 is 600.

d. 1.7 ÷ 0.1

Answer: 1.7 ÷ 0.1 = 17.

Explanation: The division of 1.7 ÷ 0.1 is 17.

e. 31 ÷ 0.01

Answer: 31 ÷ 0.01 = 3,100.

Explanation: The division of 31 ÷ 0.01 is 3,100.

f. 11 ÷ 0.01

Answer: 11 ÷ 0.01 = 1,100.

Explanation: The division of 11 ÷ 0.01 is 1,100.

g. 125 ÷ 0.1

Answer: 125 ÷ 0.1 = 1,250.

Explanation: The division of 125 ÷ 0.1 is 1,250.

h. 3.74 ÷ 0.01

Answer: 3.74 ÷ 0.01 = 374.

Explanation: The division of 3.74 ÷ 0.01 is 374.

i. 12.5 ÷ 0.01

Answer: 12.5 ÷ 0.01 = 1,250.

Explanation: The division of 12.5 ÷ 0.01 is 1,250.

Question 3. Yung bought $4.60 worth of bubble gum. Each piece of gum cost $0.10. How many pieces of bubble gum did Yung buy?

Answer: Yung bought 46 pieces of gum.

Explanation: Here, Yung bought $4.60 worth of bubble gum, and each piece of gum cost $0.10. So the number of pieces of bubble gum did Yung bought is $4.60 ÷ $0.10 = $46. So Yung bought 46 pieces of gum.

Question 4. Cheryl solved a problem: 84 ÷ 0.01 = 8,400. Jane said, “Your answer is wrong because when you divide, the quotient is always smaller than the whole amount you start with, for example, 6 ÷ 2 = 3 and 100 ÷ 4 = 25.” Who is correct? Explain your thinking.

Answer: Some examples are, 84 ÷ 1 = 84, 84 ÷ 10 = 8.4, 84 ÷ 0.1 = 840.

Explanation: Cheryl is correct and Jane is correct only some of the time and Cheryl can help Jane understand by showing some examples like, 84 ÷ 1 = 84, 84 ÷ 10 = 8.4, 84 ÷ 0.1 = 840.

Question 5. The U.S. Mint sells 2 ounces of American Eagle gold coins to a collector. Each coin weighs one-tenth of an ounce. How many gold coins were sold to the collector? Answer: The number of gold coins was sold to the collector is 20 gold coins.

Explanation: Here, U.S. Mint sells 2 ounces of American Eagle gold coins to a collector and each coin weighs one-tenth of an ounce, so the number of gold coins were sold to the collector is 2 ÷ 1/10 which is 2 ÷ 0.1 = 20 gold coins.

Eureka Math Grade 5 Module 4 Lesson 29 Exit Ticket Answer Key

Question 1. 8.3 is equal to _______ tenths _______ hundredths Answer: 83 tenths 830 hundredths.

Explanation: Given that the number is 8.3 which is equal to 83 tenths and 830 hundred.

Question 2. 28 is equal to _______ hundredths _______ tenths Answer: 2800 tenths 830 hundredths.

Question 3. 15.09 ÷ 0.01 = _______ Answer: 15.09 ÷ 0.01 = 1,509.

Explanation: Given that the equation is 15.09 ÷ 0.01 which is equal to 1,509.

Question 4. 267.4 ÷ \(\frac{1}{10}\) = _______ Answer: 267.4 ÷ \(\frac{1}{10}\) = 2,674

Explanation: Given that the equation is 267.4 ÷ \(\frac{1}{10}\) which is equal to 2,674.

Question 5. 632.98 ÷ \(\frac{1}{100}\) = _______ Answer: 632.98 ÷ \(\frac{1}{100}\) = 63,298

Explanation: Given that the equation is 632.98 ÷ \(\frac{1}{100}\) which is equal to 63,298.

Eureka Math Grade 5 Module 4 Lesson 29 Homework Answer Key

Question 1. Divide. Rewrite each expression as a division sentence with a fraction divisor, and fill in the blanks. The first one is done for you. a. 9 ÷ 0.1 There are ______ tenths in 1 whole. There are ______ tenths in 9 wholes.

Answer: There are 10 tenths in 1 whole. There are 90 tenths in 9 wholes.

Explanation: Given that 9 ÷ 0.1 which is 90. In that, there are 10 tenths in 1 whole and there are 90 tenths in 9 wholes.

b. 6 ÷ 0.1 There are ______ tenths in 1 whole. There are ______ tenths in 6 wholes.

Answer: There are 10 tenths in 1 whole. There are 60 tenths in 6 wholes.

Explanation: Given that 6 ÷ 0.1 which is 60. In that, there are 10 tenths in 1 whole and there are 60 tenths in 6 wholes.

c. 3.6 ÷ 0.1 There are ______ tenths in 3 wholes. There are ______ tenths in 6 tenths. There are ______ tenths in 3.6.

Answer: There are 30 tenths in 3 wholes. There are 6 tenths in 6 tenths. There are 36 tenths in 3.6.

Explanation: Given that 3.6 ÷ 0.1 which is 36. In that, there are 30 tenths in 3 wholes and there are 6 tenths in 6 tenths and there are 36 tenths in 3.6.

d. 12.8 ÷ 0.1 There are ______ tenths in 12 wholes. There are ______ tenths in 8 tenths. There are ______ tenths in 12.8.

Answer: There are 120 tenths in 12 wholes. There are 8 tenths in 8 tenths. There are 128 tenths in 12.8.

Explanation: Given that 12.8 ÷ 0.1 which is 128. In that, there are 120 tenths in 12 wholes and there are 8 tenths in 8 tenths and there are 128 tenths in 12.8.

e. 3 ÷ 0.1 There are ______ tenths in 1 whole. There are ______ tenths in 3 wholes.

Answer: There are 100 tenths in 1 whole. There are 300 tenths in 3 wholes.

Explanation: Given that 3 ÷ 0.1 which is 30. In that, there are 100 tenths in 1 whole and there are 300 tenths in 3 wholes.

f. 7 ÷ 0.1 There are ______ tenths in 1 whole. There are ______ tenths in 7 wholes.

Answer: There are 100 tenths in 1 whole. There are 700 tenths in 7 wholes.

Explanation: Given that 7 ÷ 0.1 which is 70. In that, there are 100 tenths in 1 whole and there are 700 tenths in 7 wholes.

g. 4.7 ÷ 0.01 There are ______ tenths in 4 wholes. There are ______ tenths in 7 tenths. There are ______ tenths in 4.7.

Answer: There are 400 tenths in 4 wholes. There are 70 tenths in 7 tenths. There are 470 tenths in 4.7.

Explanation: Given that 4.7 ÷ 0.01 which is 470. In that, there are 400 tenths in 4 wholes and there are 70 tenths in 7 tenths and there are 470 tenths in 4.7.

h. 11.3 ÷ 0.01 There are ______ tenths in 11 wholes. There are ______ tenths in 3 tenths. There are ______ tenths in 11.3.

Answer: There are 1100 tenths in 11 wholes. There are 30 tenths in 3 tenths. There are 1130 tenths in 11.3.

Explanation: Given that 11.3 ÷ 0.01 which is 1,130. In that, there are 1100 tenths in 11 wholes and there are 30 tenths in 3 tenths and there are 1130 tenths in 11.3.

Question 2. Divide. a. 2 ÷ 0.1

Answer: 2 ÷ 0.1 = 20.

Explanation: The division of 2 ÷ 0.1 is 20.

b. 23 ÷ 0.1

Answer: 23 ÷ 0.1 = 230.

Explanation: The division of 23 ÷ 0.1 is 230.

c. 5 ÷ 0.01

Answer: 5 ÷ 0.01 = 500.

Explanation: The division of 5 ÷ 0.01 is 500.

d. 7.2 ÷ 0.1

Answer: 7.2 ÷ 0.1 = 72.

Explanation: The division of 7.2 ÷ 0.1 is 72.

e. 51 ÷ 0.01

Answer: 51 ÷ 0.01 = 5,100.

Explanation: The division of 51 ÷ 0.01 is 5,100.

f. 31 ÷ 0.1

Answer: 31 ÷ 0.1 = 310.

Explanation: The division of 31 ÷ 0.1 is 310.

g. 231 ÷ 0.1

Answer: 231 ÷ 0.1 = 2,310.

Explanation: The division of 231 ÷ 0.1 is 2,310.

h. 4.37 ÷ 0.01

Answer: 4.37 ÷ 0.01 = 437.

Explanation: The division of 4.37 ÷ 0.01 is 437.

i. 24.5 ÷ 0.01

Answer: 24.5 ÷ 0.01 = 2,450.

Explanation: The division of 24.5 ÷ 0.01 is 2,450.

Question 3. Giovanna is charged $0.01 for each text message she sends. Last month, her cell phone bill included a $12.60 charge for text messages. How many text messages did Giovanna send? Answer: The number of text messages did Giovanna send is 1,260.

Explanation: Here, Giovanna is charged $0.01 for each text message she sends, and in last month, her cell phone bill included a $12.60 charge for text messages. So the number of text messages did Giovanna send is $12.60 ÷ $0.01 which is 1,260.

Question 4. Geraldine solved a problem: 68.5 ÷ 0.01 = 6,850. Ralph said, “This is wrong because a quotient can’t be greater than the whole you start with. For example, 8 ÷ 2 = 4 and 250 ÷ 5 = 50.” Who is correct? Explain your thinking. Answer: Geraldine was correct.

Explanation: Geraldine was correct. As quotient can be greater than the whole start. So Geraldine was correct.

Question 5. The price for an ounce of gold on September 23, 2013, was $1,326.40. A group of 10 friends decide to equally share the cost of 1 ounce of gold. How much money will each friend pay? Answer: Each friend pays $1326.40 ÷ 10 which is $132.64.

Explanation: Here, the price for an ounce of gold on September 23, 2013, was $1,326.40 and a group of 10 friends decide to equally share the cost of 1 ounce of gold. So each friend pays $1326.40 ÷ 10 which is $132.64.

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Eureka Math Grade 5 Module 2 Lesson 23 Answer Key

Engage ny eureka math 5th grade module 2 lesson 23 answer key, eureka math grade 5 module 2 lesson 23 problem set answer key.

Question 1. Divide. Then, check using multiplication.

a. 4,859 ÷ 23

Answer: 4859/23 = 6.

eureka math lesson 29 homework answers key grade 5

b. 4,368 ÷ 52

Answer: 4368/52 = 0.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-2

c. 7,242 ÷ 34

Answer: 7242/34 = 0.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-3

d. 3,164 ÷ 45

Answer: 3164/45 = 5.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-4

e. 9,152 ÷ 29

Answer: 9152/29 = 17.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-5

f. 4,424 ÷ 63

Answer: 4424/63 = 22.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-6

Question 2. Mr. Riley baked 1,692 chocolate cookies. He sold them in boxes of 36 cookies each. How much money did he collect if he sold them all at $8 per box?

Answer: The money did she collect = $5.9.

Explanation: In the above-given question, given that, Mr. Riley baked 1692 chocolate cookies. he sold them in boxes of 36 cookies each. 36x 8 = 288. 1692/288. 5.9$.

Question 3. 1,092 flowers are arranged into 26 vases, with the same number of flowers in each vase. How many flowers would be needed to fill 130 such vases?

Answer: The number of flowers needed to fill 130 such vases = 8 flowers.

Explanation: In the above-given question, given that, 1092 flowers are arranged into 26 vases, with the same number of flowers in each vase. 1092/26 = 42. 1092/130 = 8.4.

Question 4. The elephant’s water tank holds 2,560 gallons of water. After two weeks, the zookeeper measures and finds that the tank has 1,944 gallons of water left. If the elephant drinks the same amount of water each day, how many days will a full tank of water last?

Answer: The number of days will a full tank of water last = 4.15 gallons.

Explanation: In the above-given question, given that, The elephant’s water tank holds 2560 gallons of water. after two weeks, the zookeeper measures and finds that the tank has 1944 gallons of water left. if the elephant drinks the same amount of water each day. 2560 – 1944. 616. 2560/616. 4.15 gallons.

Eureka Math Grade 5 Module 2 Lesson 23 Exit Ticket Answer Key

Divide. Then, check using multiplication. a. 8,283 ÷ 19

Answer: 8283/41 = 1.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-7

b. 1,056 ÷ 37

Answer: 1056/37 = 20.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-8

Eureka Math Grade 5 Module 2 Lesson 23 Homework Answer Key

Question 1. Divide. Then, check using multiplication. a. 9,962 ÷ 41

Answer: 9962/41 = 40.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-9

b. 1,495 ÷ 45

Answer: 1495/45 = 10.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-10

c. 6,691 ÷ 28

Answer: 6691/28 = 27.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-11

d. 2,625 ÷ 32

Answer: 2625/32 = 33.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-12

e. 2,409 ÷ 19

Answer: 2409/19 = 15.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-13

f. 5,821 ÷ 62

Answer: 5821/62 = 55.

Eureka-Math-Grade-5-Module-2-Lesson-23-Answer Key-14

Question 2. A political gathering in South America was attended by 7,910 people. Each of South America’s 14 countries was equally represented. How many representatives attended from each country?

Answer: The representatives attend from each country = 565.

Explanation: In the above-given question, given that, A political gathering in south America was attended by 7910 people. each of south America’s 14 countries was equally represented. 7910/14 = 565.

Question 3. A candy company packages caramel into containers that hold 32 fluid ounces. In the last batch, 1,848 fluid ounces of caramel were made. How many containers were needed for this batch?

Answer: The containers were needed for this batch = 58 containers.

Explanation: In the above-given question, given that, A candy company packages caramel into containers that hold 32 fluid ounces. In the last batch, 1,848 fluid ounces of caramel were made. 1848/32. 57.75. 58.

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  3. Engage NY // Eureka Math Grade 5 Module 4 Lesson 29 Homework

    eureka math lesson 29 homework answers key grade 5

  4. Eureka Math Module 5 Lesson 29 Homework

    eureka math lesson 29 homework answers key grade 5

  5. Eureka math grade 5 module 5 lesson 15 problem set common core

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  6. EngageNY (Eureka Math) Grade 5 Module 5 Answer Key by MathVillage

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  1. Eureka math grade 5 module 4 lesson 29 homework

  2. Engage NY // Eureka Math Grade 5 Module 5 Lesson 18 Homework

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  5. Eureka Math Module 3 Lesson 29 Homework

  6. Eureka Math Module 5 Lesson 29 Homework

COMMENTS

  1. Eureka Math Grade 5 Module 4 Lesson 29 Answer Key

    Eureka Math Grade 5 Module 4 Lesson 29 Problem Set Answer Key. Question 1. Divide. Rewrite each expression as a division sentence with a fraction divisor, and fill in the blanks. The first one is done for you. Example: 2 ÷ 0.1 = 2 ÷ 110 = 20. There are 10 tenths in 1 whole. There are 20 tenths in 2 wholes. a. 5 ÷ 0.1.

  2. Engage NY // Eureka Math Grade 5 Module 4 Lesson 29 Homework

    Engage NY // Eureka Math Grade 5 Module 4 Lesson 29 Homework. Engage NY // Eureka Math Grade 5 Module 4 Lesson 29 Homework.

  3. Eureka Math Grade 5 Module 2 Lesson 29 (updated)

    EngageNY/Eureka Math Grade 5 Module 2 Lesson 29For more videos, please visit http://bit.ly/eurekapusdPLEASE leave a message if a video has a technical diffic...

  4. Eureka math grade 5 module 2 lesson 29 homework

    Solve division word problems involving multi digit division with group size unknown and the number of groups unknown, help teachers, help parents, help students

  5. PDF Grade 5, Module 5 Student File A

    This book may be purchased from the publisher at eureka-math.org 10 9 8 7 6 5 4 3 2 1 Eureka Math™ Grade 5, Module 5 Student File_A Contains copy-ready classwork and homework as well as templates (including cut outs)

  6. Eureka Math Student Materials: Grades K-5

    Bundle options are available for all of our materials (print, digital, PD, etc.). Prices vary by grade and size of class set. Certain grade-levels do not include all packets due to the nature of the grade-level content. Student workbooks are available in class sets of 20, 25, and 30. Prices vary by size of class set.

  7. 5th Grade Math (Eureka Math/EngageNY)

    Unit 5: Module 5: Addition and multiplication with volume and area. 0/1400 Mastery points. Topic A: Concepts of volume Topic B: Volume and the operations of multiplication and addition Topic C: Area of rectangular figures with fractional side lengths. Topic D: Drawing, analysis, and classification of two-dimensional shapes.

  8. Course: G5M4: Multiplication and Division of Fractions and Decimal

    Multiplication and Division of Fractions and Decimal Fractions. Eureka Essentials: Grade 5. An outline of learning goals, key ideas, pacing suggestions, and more! Fluency Games. Teach Eureka Lesson Breakdown. Downloadable Resources. Teacher editions, student materials, application problems, sprints, etc. Application Problems.

  9. Eureka math grade 5 module 4 lesson 29 homework

    Connect division by a unit fraction to division by 1 tenth and 1 hundredth, common core, word problems, help students, help teachers, help parents

  10. Printed Materials

    As the creator of Engage NY Math and Eureka Math, Great Minds is the only place where you can get print editions of the PK-12 curriculum.Our printed materials are available in two configurations: Learn, Practice, Succeed, or student workbooks, teacher editions, assessment and fluency materials. The Learn, Practice, Succeed configuration is available for grades K-8 and offers teachers ...

  11. Eureka Math Grade 5 Module 2 Lesson 29 Answer Key

    Eureka Math Grade 5 Module 2 Lesson 29 Problem Set Answer Key. Solve. Question 1. Lamar has 1,354.5 kilograms of potatoes to deliver equally to 18 stores. 12 of the stores are in the Bronx. How many kilograms of potatoes will be delivered to stores in the Bronx? The kilograms of potatoes will be delivered to stores in the Bronx = 225.75 kg.

  12. Eureka Math Grade 5 Module 4 Lesson 29 Answer Key

    Eureka Math Grade 5 Module 4 Lesson 29 Problem Set Answer Key. Question 1. Divide. Rewrite each expression as a division sentence with a fraction divisor, and fill in the blanks. The first one is done for you. Example: 2 ÷ 0.1 = 2 ÷ = 20. There are 10 tenths in 1 whole. There are 20 tenths in 2 wholes. a. 5 ÷ 0.1.

  13. Eureka Math Grade 4 Module 5 Lesson 29

    EngageNY/Eureka Math Grade 4 Module 5 Lesson 29For more videos, please visit http://bit.ly/eurekapusdPLEASE leave a message if a video has a technical diffic...

  14. Eureka Math Grade 5 Module 2 Lesson 23 Answer Key

    Engage NY Eureka Math 5th Grade Module 2 Lesson 23 Answer Key Eureka Math Grade 5 Module 2 Lesson 23 Problem Set Answer Key. Question 1. Divide. Then, check using multiplication. a. 4,859 ÷ 23. Answer: 4859/23 = 6. Explanation: In the above-given question, given that, Divide, and then check. 23 x 2 = 46. 48 - 46 = 2. 23 x 1 = 23. 29-23 = 6 ...