neco chemistry essay and objective answer 2023

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NECO Chemistry Questions and Answers 2023/2024 (Essay and Objectives)

NECO Chemistry Questions and Answers 2023. I will be showing you past Chemistry objectives and theory repeated questions for free in this post. You will also understand how  NECO  Chemistry questions are set and how to answer them.

The National Examinations Council (NECO) is an examination body in Nigeria that conducts the Senior Secondary Certificate Examination and the General Certificate in Education in June/July and December/January respectively.

Table of Contents

NECO Chemistry Objectives and Essay Answers 2023 (Expo)

The 2023 NECO Chemistry expo will be posted here today 24th July during the NECO Chemistry examination. Keep checking and reloading this page for the answers.

NECO 2023 Chemistry Answers Loading.

OBJ Answers:

1-10: DEADADECAD

11-20: BAEDDBDBAE

21-30: CCDCABDDCD

31-40: EBEECEBCEE

41-50: BCCECDDADD

51-60: DABBDEAECA

————————————————————————————————————-

NECO Chemistry Questions and Answers For Practice

The following NECO Chemistry questions are questions to expect in the 2023 NECO examination.

1. The minimum amount of energy required for effective collisions between reacting particles is known A) Activation energy B) Bond energy C) Kinetic energy D) Potential energy

2. The bond formed between H2OH2O and H+H+ to form the hydroxonium H3O+H3O+ is A) Dative B) Covalent C) Electrovalent D) Ionic

3. An element XX forms the following oxides X2O,XOX2O,XO and XO2.XO2. This phenomenon illustrates the law of ________. A) Conservation of mass B) Definite proportion C) Mass action D) Multiple proportion

4.. How many moles of oxygen would contain 1.204×10241.204×1024 molecules? NB: Avogadro’s constant (NA) =6.02×1023=6.02×1023 A) 1 B) 2 C) 3 D) 4

See: NECO Timetable

5. Which of the following statements about solids is correct? A) Solid particles are less orderly than those of a liquid B) Solid have lower densities than liquids C) Solid particles have greater kinetic energies than those of liquids D) Solid particles cannot be easily compressed

6. Which of the following apparatus can be used to measure a specific volume of a liquid accurately? A) Beaker B) Conical flask C) Measuring cyclinder D) Pipette

7. The general gas equation PVT=KPVT=K is a combination of A) Boyle’s and Charles’ laws B) Boyle’s and Graham’s laws C) Charles’ and Graham’s laws D) Dalton’s and Graham’s laws

8. The spreading of the scent of a flower in a garden is an example of? A) Brownian motion B) Diffusion C) Osmosis D) Tynadal effect

9. Propane and carbon (IV) oxide diffuse at the same rate because [H = 1.00, C = 12.0, O = 16.0] Options A) They are both gases B) Their molecules contain carbon C) They have the same relative molecular mass D) Both are denser than air

1O. The energy which accompanies the addition of an electron to an isolated gaseous atom is A) Atomization B) Electronegativity C) Electron affinity D) Ionization

11. A sample of hard water contains some calcium sulphate and calcium hydrogen carbonate. The total hardness may therefore be removed by A. boiling the water B. adding excess calcium hydroxide C. adding a calculated amount of calcium hydroxide D. adding sodium carbonate E. adding magnesium hydroxide

12. During the electrolysis of copper II sulphate between platinum electrodes, if litmus solution is added to the anode compartment, A. the litmus turns blue but no gas is evolved B. the litmus turns blue and oxygen is evolved C. the litmus turns blue and hydrogen is evolved D. the litmus turns red and oxygen is evolved E. the litmus turns red and then becomes colourless

13. The reaction between an organic acid and an alcohol in the presence of an acid catalyst is known as; A. saponification B. dehydration C. esterification D. hydrolysis E. hydration

14. The IUPAC names of the compounds CH3COOH and CH2=CH2 are respectively; A. acetic acid and ethane B. ethanoic acid and ethene C. methanoic acid and ethylene D. ethanol and ethene E. acetic acid and ethylene

15. If 30cm3 of oxygen diffuses through a porous pot in 7 seconds, how long will it take 60cm3 of chlorine to diffuse through the same pot, if the vapour densities of oxygen and chlorine are 16 and 36 respectively? A. 9.3 sec B. 14 sec C. 21 sec D. 28 sec E. 30.3 sec

16. When heat is absorbed during a chemical reaction, the reaction is said to be A. thermodynamic B. exothermic C. isothermal D. endothermic E. thermostatic

17. When large hydrocarbon molecules are heated at high temperature in the presence of a catalyst to give smaller molecules, the process is known as A. disintegration B. polymerization C. cracking D. degradation E. distillation

18. The pH of four solutions W, X, Y, Z are 4, 6, 8, 10 respectively, therefore A. none of these solutions is acidic B. the pH of Y is made more acidic by addition of distilled water C. Z is the most acidic solution D. W is the most acidic solution E. X is neutral

19. When each of the nitrates of Potassium, Magnesium and iron is heated, A. all the nitrates decompose to their oxides B. the nitrate of magnesium gives the nitrite and oxygen C. the nitrates of iron magnesium and iron give the oxides D. the nitrate of iron gives the nitrite and oxygen E. the nitrate of the magnesium is not decomposed

2O. Which of the following metals cannot replace hydrogen from water or steam? A. Sodium B. Magnesium C. Iron D. Calcium E. Copper

21. small quantity of solid ammonium chloride (NH4Cl) was heated gently in a test tube, the solid gradually disappears to produce two gases. Later, a white cloudy deposit was observed on the cooler part of the test tube. The ammonium chloride is said to have undergone A. distillation B. sublimation C. precipitation D. evaporation E. decomposition

22. Elements P, Q, R, S have 6, 11, 15, 17 electrons respectively, therefore, A. P will form an electrovalent bond with R B. Q will form a covalent bond with S C. R will form an electrovalent bond with S D. Q will form an electrovalent bond with S E. Q will form a covalent bond with R

23. An element X forms the following compounds with chlorine; XCl4, XCl3, XCl2. This illustrates the A. law of multiple proportions B. law of chemical proportions C. law of simple proportions D. law of conservation of mass E. law of definite proportions

24. The oxidation state of chlorine in potassium chlorate is A. +1 B. +2 C. +3 D. +5 E. +7

25. 10 When air which contains the gases Oxygen, nitrogen, carbondioxide, water vapour and the rare gases, is passed through alkaline pyrogallol and then over quicklime, the only gases left are; A. nitrogen and carbondioxide B. the rare gases C. nitrogen and oxygen D. nitrogen and the rare gases E. nitrogen, carbondioxide and the rare

26. Which of the following statements is NOT correct? A. The average kinetic energy of a gas is directly proportional to its temperature B. At constant tempearture, the volume of a gas increases as the pressure increases C. The pressure of a gas is inversely proportional to its volume D. The temperature of a gas is directly proportional to its volume E. The collisions of molecules with each other are inelastic

27. Zinc Oxide is a A. Basic Oxide B. Acidic Oxide C. Amphoteric Oxide D. Neutral Oxide E. Reactive Oxide

28. When sodium chloride and metallic sodium are each dissolved in water A. both processes are exothermic B. both processes are endothermic C. the dissolution of metallic sodium is endothermic D. the dissolution of metallic sodium is exothermic E. the dissolution of sodium chloride is explosive

29. The periodic classification of elements is an arrangement of the elements in order of their A. Atomic Weights B. Isotopic Weights C. Molecular Weights D. Atomic Numbers E. Atomic Masses

3O. In the reaction between sodium hydroxide and sulphuric acid solutions, what volume of 0.5 molar sodium hydroxide would exactly neutralise 10cm3 of 1.25 molar sulphuric acid? A. 5cm3 B. 10cm3 C. 20cm3 D. 25cm3 E. 50cm3

Recommended: How to check NECO Result

NECO Chemistry Questions And Answers 2023 (Paper 2)

Don’t worry about these NECO Chemistry Questions And Answers 2023. All you need to do is to keep on refreshing this page for the 2023 NECO Chemistry Questions And Answers for this year. It will be posted here in few minutes.

Tips on How to Pass 2023 NECO Chemistry Examinations

The following guidelines will help you pass the 2023 NECO Chemistry examination with flying colours.

Have a Target and Work Towards Actualizing it 

You have decided to pass NECO Chemistry 2023 and I am sure of that. Now, the next thing you should do is set targets.

You have told yourself, “I will score A in NECO Chemistry 2023”, that’s not all. You need to plan on how to make it happen. Create a timetable and master plan to achieve your goals.

 Get the Recommended Textbook on Chemistry for 2023 NECO Examination

Normally, NECO recommends books for the examination. But apart from NECO Literature in English where certain novels are compulsory, you are free to use any good Chemistry textbook to prepare for NECO 2023 exam.

Some textbooks are more difficult to understand. If you have any topic you are finding difficult to understand, then get a textbook that will simplify the topics and make life better for you.

 Do not Skip Chemistry Examples and Exercise you Will Come Across While Reading: 

Many candidates are fond of skipping exercises and even examples while studying textbooks. In fact, we like notebooks so much that we could ask, “can I read my notebook and pass NECO Chemistry 2023?” Don’t be scared of attempting exercises in Biology. Face the challenges.

If you have any questions about the  NECO Chemistry Questions and Answers 2023 , kindly drop your question in the comment box.

Last Updated on July 25, 2023 by Admin

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122 thoughts on “NECO Chemistry Questions and Answers 2023/2024 (Essay and Objectives)”

Please when will the answer come up

I just need questions for the two

I am really greatfull for the coperation you showed to us most especially me if not for you guys thisneco would have been trouble so sincear thank you

WHERE IS THE ANSWER FOR THE OBJ QUESTIONS THAT IS UP THERE

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NECO Chemistry Questions and Answers 2023 Objectives and Essay

Neco chemistry 2023 answers are now available. neco chemistry questions and answers 2023/2024 objective and essay and other exam details for neco 2023 are on this page. see the 2023 neco chemistry answers for both objective and theory below. get the neco chemistry objective and essay answers here. the 2023 chemistry neco obj and theory […] the post neco chemistry questions and answers 2023 objectives and essay appeared first on study forum..

NECO chemistry 2023 answers are now available. NECO chemistry questions and answers 2023/2024 objective and essay and other exam details for NECO 2023 are on this page. See the 2023 NECO chemistry answers for both objective and theory below. Get the NECO chemistry objective and essay answers here.

The 2023 chemistry NECO OBJ and theory questions and answers are provided here for free. All you have to do is to go through the questions and take note of the NECO chemistry answers 2023. Read on to find out.

NECO Chemistry Questions and Answers 2023 Objective and Essay

Have you been searching on Google in order to get the NECO chemistry questions and answers 2023? If so, we have got you covered!

We have the 2023 NECO chemistry questions and our team of experts will soon upload the NECO chemistry questions and their accurate answers to help you pass the 2023 NECO chemistry examination.

The 2023 NECO chemistry theory questions and OBJ will be uploaded any moment from now. So if you are searching for the NECO chemistry answers 2023 for objective and theory, then you are on the right page. See NECO chemistry objective and essay questions and answers below.

NECO Chemistry Answers 2023 Objective and Theory

The National Examination Council (NECO) is an examination body in Nigeria that conducts the Senior Secondary Certificate Examination and the General Certificate in Education in June/July and November/December respectively.

The 2023 NECO chemistry questions are set from the SS1 to SS3 chemistry syllabus. So all the questions you will encounter in this year’s examination are in the syllabus, and nearly 95% of the questions are repeated.

You don’t have to worry about the 2023 NECO chemistry questions and answers PDF (essay and objective). The NECO chemistry answers 2023 will be uploaded any moment from now. All you need to do is to keep refreshing this page so as not to miss out.

Once again, keep refreshing this page because we will upload the original NECO chemistry questions and answers for this year’s exams on this page at any moment from now. Also, to download the past questions and answers, click on this link NECO chemistry past questions .

If you have any questions about the NECO chemistry questions 2023 and answers, feel free to use the comment box below or use the Chat With Us button and we will respond immediately.

The 2023 NECO chemistry answers will be posted here. Be patient. Keep checking and reloading this page for the correct answers. NECO 2023 chemistry answers loading…….

There is nothing like NECO chemistry expo 2023 online. All students are advised to avoid all patronizing online fraudsters/vendors who claim to provide such services.

The post NECO Chemistry Questions and Answers 2023 Objectives and Essay appeared first on Study Forum .

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NECO Chemistry Questions and Answers 2023 Objectives and Essay

• Post author: Study Admin
• Post published: October 26, 2023
• Post category: School News
• Post comments: 0 Comments

NECO chemistry 2023 answers are now available. NECO chemistry questions and answers 2023/2024 objective and essay and other exam details for NECO 2023 are on this page. See the 2023 NECO chemistry answers for both objective and theory below. Get the NECO chemistry objective and essay answers here.

The 2023 chemistry NECO OBJ and theory questions and answers are provided here for free. All you have to do is to go through the questions and take note of the NECO chemistry answers 2023. Read on to find out.

NECO Chemistry Questions and Answers 2023 Objective and Essay

Have you been searching on Google in order to get the NECO chemistry questions and answers 2023? If so, we have got you covered!

We have the 2023 NECO chemistry questions and our team of experts will soon upload the NECO chemistry questions and their accurate answers to help you pass the 2023 NECO chemistry examination.

The 2023 NECO chemistry theory questions and OBJ will be uploaded any moment from now. So if you are searching for the NECO chemistry answers 2023 for objective and theory, then you are on the right page. See NECO chemistry objective and essay questions and answers below.

NECO Chemistry Answers 2023 Objective and Theory

The National Examination Council (NECO) is an examination body in Nigeria that conducts the Senior Secondary Certificate Examination and the General Certificate in Education in June/July and November/December respectively.

The 2023 NECO chemistry questions are set from the SS1 to SS3 chemistry syllabus. So all the questions you will encounter in this year’s examination are in the syllabus, and nearly 95% of the questions are repeated.

You don’t have to worry about the 2023 NECO chemistry questions and answers PDF (essay and objective). The NECO chemistry answers 2023 will be uploaded any moment from now. All you need to do is to keep refreshing this page so as not to miss out.

Once again, keep refreshing this page because we will upload the original NECO chemistry questions and answers for this year’s exams on this page at any moment from now. Also, to download the past questions and answers, click on this link NECO chemistry past questions .

If you have any questions about the NECO chemistry questions 2023 and answers, feel free to use the comment box below or use the Chat With Us button and we will respond immediately.

The 2023 NECO chemistry answers will be posted here. Be patient. Keep checking and reloading this page for the correct answers. NECO 2023 chemistry answers loading…….

There is nothing like NECO chemistry expo 2023 online. All students are advised to avoid all patronizing online fraudsters/vendors who claim to provide such services.

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NECO Chemistry Questions and Answers 2023 (100% Sure) Theory & Obj Solution

Get free Verified NECO Chemistry Questions and Answers 2023.  NECO June/July Free Chemistry EXPO answers.  National Examination Council Chemistry Theory and Objective Answers for you to have good NECO result. You will also understand how NECO Chemistry questions are set and how to answer them. The National Examination Council is an examination body in Nigeria that conducts the Senior Secondary Certificate Examination and the General Certificate in Education in June/July and November/December respectively.

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CHEMISTRY-OBJ

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CHEMISTRY-Obj! 1-10   DEADADECAD 11-20 BAEDDBDBAE 21-30 CCDCABDDCD 31-40 EBEECEBCEE 41-50 BCCECDDADD 51-60 DABBDEAECA Solved By beafans.com Completed!!

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CHEMISTRY-ANSWERS

(1ai) (i) Manufacturing sulfuric acid (ii) Vulcanization of rubber (iii) Formulation of Pesticides and fungicides

(1aii) (i) It is a colorless gas that has a distinct smell of rotten eggs (ii) Hydrogen sulphide is soluble in water to some extent

(1aiii) Soaps are made from natural products while detergents are made from synthetic products.

(1aiv) Detergents is for household cleaning and laundry purposes

(1bi) Number of neutrons = Mass number (A) – Atomic number (Z)

I. ²³₁₁X A = 23 (mass number) Z = 11 (atomic number)

Number of neutrons = 23 – 11 = 12

II. ³⁹₁₉Y A = 39 (mass number) Z = 19 (atomic number)

Number of neutrons = 39 – 19 = 20

(1bii) Molar mass: Na = 22.99 g/mol O₂ = 2 * 16.00 g/mol = 32.00 g/mol

Now, let’s calculate the mass of oxygen needed:

First, calculate the number of moles of sodium (Na) in 9.2g: Number of moles = Mass / Molar mass Number of moles of Na = 9.2g / 22.99 g/mol ≈ 0.4002 mol

Since the mole ratio of Na to O₂ is 4:1, the number of moles of O₂ needed is: Number of moles of O₂ = 0.4002 mol / 4 ≈ 0.1001 mol

Now, calculate the mass of oxygen needed: Mass of O₂ = Number of moles of O₂ * Molar mass of O₂ Mass of O₂ = 0.1001 mol * 32.00 g/mol ≈ 3.204 g

Therefore, approximately 3.204 grams of oxygen are needed to burn 9.2 grams of sodium.

(1biii) CaCO₃(s) + 2 HCl(aq) —> CaCl₂(aq) + CO₂(g) + H₂O(l)

From the balanced equation, 1 mole of calcium carbonate (CaCO₃) reacts with 2 moles of HCl to produce 1 mole of calcium chloride (CaCl₂).

Molar masses: CaCO₃ = Ca(40.08) + C(12.01) + 3O(16.00) = 100.09 g/mol CaCl₂ = Ca(40.08) + 2Cl(35.45) = 110.98 g/mol

Now, let’s calculate the number of moles of CaCO₃ in 50g:

Number of moles of CaCO₃ = Mass / Molar mass Number of moles of CaCO₃ = 50g / 100.09 g/mol ≈ 0.4998 mol

Since the mole ratio of CaCO₃ to CaCl₂ is 1:1, the number of moles of CaCl₂ that can be obtained is also approximately 0.4998 mol.

Thus, about 0.4998 moles of calcium chloride can be obtained from 50g of limestone in the presence of excess hydrogen chloride.

(1ci) (i) Sol: A sol is a colloidal solution in which solid particles are dispersed in a liquid medium. (ii) Aerosol: An aerosol is a colloidal solution in which liquid or solid particles are dispersed in a gas medium.

(1cii) The law of definite proportions, also known as the law of constant composition, states that a given chemical compound always contains its constituent elements in fixed and definite proportions by mass. This means that the ratio of the masses of the elements in a compound is constant, regardless of the compound’s origin or method of preparation.

(I) Sodium trioxonitrate (V) is also known as sodium nitrate, with the chemical formula NaNO₃.

The atomic masses are as follows: Na (Sodium) = 22.99 g/mol N (Nitrogen) = 14.01 g/mol O (Oxygen) = 16.00 g/mol

Relative molecular mass of NaNO₃ = (1 * Na) + (1 * N) + (3 * O) Relative molecular mass of NaNO₃ = (1 * 22.99 g/mol) + (1 * 14.01 g/mol) + (3 * 16.00 g/mol) Relative molecular mass of NaNO₃ = 22.99 g/mol + 14.01 g/mol + 48.00 g/mol Relative molecular mass of NaNO₃ = 85.00 g/mol

Therefore, the relative molecular mass of sodium nitrate (NaNO₃) is 85.00 g/mol.

(II) Copper (II) trioxosulphate (VI) pentahydrate is also known as copper (II) sulfate pentahydrate, with the chemical formula CuSO₄ · 5H₂O.

The atomic masses are as follows: Cu (Copper) = 63.55 g/mol S (Sulfur) = 32.06 g/mol O (Oxygen) = 16.00 g/mol H (Hydrogen) = 1.01 g/mol

Relative molecular mass of CuSO₄ · 5H₂O = (1 * Cu) + (1 * S) + (4 * O) + (10 * H) + (5 * O)

Relative molecular mass of CuSO₄ · 5H₂O = (1 * 63.55 g/mol) + (1 * 32.06 g/mol) + (4 * 16.00 g/mol) + (10 * 1.01 g/mol) + (5 * 16.00 g/mol)

Relative molecular mass of CuSO₄ · 5H₂O = 63.55 g/mol + 32.06 g/mol + 64.00 g/mol + 10.10 g/mol + 80.00 g/mol

Relative molecular mass of CuSO₄ · 5H₂O = 249.71 g/mol

If you have any questions about the NECO Chemistry theory & Obj 2023, kindly let us know in the comment box.

We are happy you are here for  the 2023 Chemistry answers. The complete solution will be made free in some minutes before  the Chemistry examination.

NECO Chemistry questions 2023, NECO 2023 Chemistry questions and answers, Chemistry NECO 2023, NECO questions 2023/2023, Chemistry 2023,

Therefore, the relative molecular mass of copper (II) sulfate pentahydrate (CuSO₄ · 5H₂O) is 249.71 g/mol.

(2ai) Mass of silver deposited (in grams) = (Current in Amperes × Time in seconds × Atomic mass of silver) / (1 Faraday)

Given: Current = 4.6 A Time = 90 minutes = 90 × 60 seconds = 5400 seconds Atomic mass of silver (Ag) = 108g/mol 1 Faraday = 96,500C

Substituting the values to calculate the mass of silver deposited:

Mass of silver deposited = (4.6 A × 5400 s × 108 g/mol) / 96,500 C

Mass of silver deposited ≈ (2,682,720 g·s/mol) / 96,500 C

Mass of silver deposited ≈ 27.8g

(2aii) (i) Electrode surface area (ii) Electrolyte temperature

(2aiii) (i) The oxidizing agent is MnO₄⁻(aq) (ii) The reducing agent is Fe²⁺(aq)

(2aiv) MnO₄⁻(aq) + 8H⁺(aq) + 5e⁻ —-> Mn²⁺ + 4H₂O(l)

(2bi) Coming

(2bii) (i) Gases have no fixed shape or volume. (ii) Gases have low density compared to solids and liquids. (iii) Gases have high kinetic energy and are in constant motion.

(2biii) Faraday’s second law of electrolysis states that the mass of a substance deposited (or liberated) during electrolysis is directly proportional to the quantity of electric charge passed through the electrolyte.

(2biv) (i) Charcoal (ii) Coal

(2bv) Na (Sodium) > Ca (Calcium) > Mg (Magnesium) > Al (Aluminum)

(3ai) (i) Butan-2-ol – Secondary alkanol (ii) 2-methylpropanol – Primary alkanol (iii) 2-methylpropan-2-ol – Tertiary alkanol

(3aii) (i) Fermentation (ii) Ethylene hydration

(3aiii) Let the relative molecular mass of gas Z be M. (Rate of diffusion of hydrogen)/(Rate of diffusion of gas Z) = √(molar mass of gas Z)/√(molar mass of hydrogen) 6/1 = (√M)/(√2) 36 = M/2 M = 2×36 M = 72

(3bi) 1s², 2s², 2p⁴

(3bii) (i) It is a colorless (ii) It is soluble in water. (iii) It is tasteless

(3biii) (i) Identify the longest chain. (ii) Name the substituents alphabetically

(3biv) C₂H₄ + O₂ —> 2CO₂ + 2H₂O

(3ci) Endothermic reaction can be defined as a form of heat reaction in which heat is absorbed from the surrounding into the reacting system.

(3cii) Zn(s) + H₂SO₄(aq) —> ZnSO₄(aq) + H₂(g)

(3ciii) Redox reaction.

(3iv) (i) For refining petrol (ii) For food processing (iii) For producing fertilizer

(4ai) A super saturated solution is a solution that contains more than the maximum amount of solute that is capable of being dissolved at a given temperature.

(4aii) 15/345 = Solubility *25/1000

Solubility =1000*15/25*345=15000/8625

Solubility = 1.79mol/dm³

(4aiii) (i) H₃0⁺ (ii) NH₄⁺ (iii) [CN]⁻₆

(4bi) (i) It has no chemical formula (ii) It can be separated physically (iii) Freezing air slowly yields different liquids at different temperatures

(4bii) (i) Noble gases (ii) Carbon (iv) oxide

(4biii) H₂SO₄ —-> 2H+ + SO₄²⁻

1 mole of H₂SO₄ = 2 mole of H⁺

0.1 mole of H₂SO₄ = 0.2 mole of H⁺ Mole = no. of H⁺/Avogadro’s constant

No. of H⁺ = Mole * Avogadro’s constant = 0.2 * 6.0*10²³ = 1.2*10²³ ions

(4biv) (i) Dative bonding (ii) Hydrogen bonding

(4bv) (i) BRASS: Constituent: Copper and zinc. Use: Brass is used in the production of musical instruments decorative items and plumbing fixtures.

(ii) BRONZE: Constituent: Copper and tin. Use: Bronze is used in the production of statues coins and various machinery.

(5ai) A base is a substance which when disolve produce hydroxyl ion (OH⁻) as the only negative ion

(5aii) (i) K₂O (ii) MgO

(5aiii) (i) it is used in printing inks and dyes (ii) it is used in making photographic chemicals

(5aiv) Aliphatic does not have good odour while an aromatic hydrocarbon has

(5av) M.m of XCl₃=10-8+(35-5*3) =10.8+106.5 =117.3 Vapour density =117.3/2=58.65

(5bi) (i) Temperature (ii) concentration (iii) surface area

(5bii) The law states that energy can neither be created nor destroyed in and isolated system.

(5biii) (i) burning of wood (ii) neutralization reaction

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NECO Chemistry Objective & Essay 2023 Questions and Answers: OBJ

Are you preparing for the National Examinations Council (NECO) Chemistry exam? Look no further! In this guide, we will provide you with valuable information and insights into the NECO Chemistry Objective & Essay 2023 questions and answers. Whether you are a student, teacher, or parent, this article will serve as your ultimate resource to excel in the upcoming examination.

Understanding the NECO Chemistry Exam

The NECO Chemistry exam is a crucial assessment for Senior Secondary School students in Nigeria. It is designed to evaluate their knowledge and understanding of various chemistry concepts and principles. The exam consists of two sections: the Objective section and the Essay section. Let’s delve into each section to gain a better understanding.

Note : This questions may not be 100% accurate, This article is meant to guide students for their exams.

Objective Section

The Objective section of the NECO Chemistry exam comprises multiple-choice questions that test your understanding of key concepts, definitions, and theories. This section requires you to choose the correct answer from the options provided. To excel in this section, it is important to have a solid foundation of chemistry principles and a thorough understanding of the subject matter.

Essay Section

The Essay section of the NECO Chemistry exam assesses your ability to apply your knowledge of chemistry to real-world scenarios. It consists of open-ended questions that require you to explain concepts, solve problems, and provide detailed explanations. This section tests your critical thinking, problem-solving, and communication skills. It is crucial to practice writing concise and coherent answers to effectively convey your understanding of the topics.

How to Prepare for the NECO Chemistry Exam

Proper preparation is key to performing well in the NECO Chemistry exam. Here are some effective strategies to help you prepare:

1. Familiarize Yourself with the Syllabus

Start by reviewing the NECO Chemistry syllabus. This will give you a clear understanding of the topics that will be covered in the exam. Pay close attention to the subtopics and ensure that you have a strong grasp of each one.

2. Create a Study Schedule

Develop a study schedule that allows you to allocate sufficient time to each topic. Divide your study sessions into manageable chunks and set specific goals for each session. Be consistent and disciplined in following your study schedule.

3. Use Recommended Textbooks and Study Guides

Utilize recommended textbooks and study guides to enhance your understanding of the subject matter. These resources provide comprehensive explanations, practice questions, and sample answers that can help you familiarize yourself with the exam format and improve your problem-solving skills.

4. Practice Past Questions

Practice makes perfect! Familiarize yourself with the format and types of questions asked in previous NECO Chemistry exams by practicing past questions. This will help you become more comfortable with the exam structure and improve your time management skills.

5. Seek Clarification and Guidance

If you encounter any difficulties or have doubts about certain topics, don’t hesitate to seek clarification from your teachers or classmates. Engage in group study sessions or join online forums where you can discuss and exchange ideas with fellow students.

6. Take Mock Exams

Simulate the exam environment by taking mock exams. This will help you assess your knowledge and identify areas that require further improvement. Analyze your performance in the mock exams and focus on strengthening your weak areas.

7. Revise and Review Regularly

Consistent revision is crucial for retaining information. Set aside time each week to revise the topics you have covered. Review your notes, textbooks, and study guides to reinforce your understanding of key concepts.

8. Develop Effective Exam Strategies

During the exam, utilize effective strategies to maximize your performance. Read each question carefully, manage your time wisely, and prioritize answering questions that you are confident about. Use diagrams, tables, and equations where applicable to support your answers and enhance clarity.

NECO Chemistry Objective & Essay 2023 Questions and Answers

Now, let’s move on to the main focus of this guide – the NECO Chemistry Objective & Essay 2023 questions and answers. While we cannot provide the exact questions that will appear in the exam, we can offer you valuable insights into the topics and concepts that you should focus on during your preparation. Here are some key areas to prioritize:

1. Atomic Structure

Understanding the structure of atoms is fundamental to chemistry. Focus on topics such as the Rutherford atomic model, atomic number, mass number, and electron configuration. Be prepared to explain the differences between atomic number and mass number and the significance of the relative atomic mass of elements.

2. Chemical Bonding

Chemical bonding plays a crucial role in determining the properties and behavior of substances. Study concepts such as ionic bonding, covalent bonding, and metallic bonding. Be able to explain the formation of different types of bonds and their properties.

3. Equilibrium

Equilibrium is a key concept in chemical reactions. Familiarize yourself with the factors that affect equilibrium, such as concentration, pressure, and temperature. Understand how changes in these factors can shift the equilibrium position and affect the composition of the system.

4. Acids, Bases, and Salts

Acids, bases, and salts are fundamental to understanding chemical reactions. Study the properties of acids and bases, pH scale, neutralization reactions, and the formation of salts. Be able to identify different types of salts and their uses.

5. Organic Chemistry

Organic chemistry focuses on the study of carbon-containing compounds. Pay attention to topics such as functional groups, isomerism, nomenclature, and reactions of organic compounds. Understand the importance of organic compounds in everyday life and their applications in various industries.

6. Chemical Kinetics

Chemical kinetics explores the rates of chemical reactions. Study factors that influence reaction rates, such as temperature, concentration, and catalysts. Be able to interpret and analyze reaction rate graphs and understand the concept of activation energy.

7. Redox Reactions

Redox reactions involve the transfer of electrons between reactants. Familiarize yourself with oxidation numbers, balancing redox equations, and identifying oxidizing and reducing agents. Understand the applications of redox reactions in various chemical processes.

8. Stoichiometry

Stoichiometry involves the calculation of quantities of reactants and products in chemical reactions. Study topics such as mole concept, empirical and molecular formulas, and stoichiometric calculations. Be able to balance chemical equations and perform calculations involving stoichiometry.

9. Thermodynamics

Thermodynamics deals with the study of energy changes in chemical reactions. Understand concepts such as enthalpy, entropy, and Gibbs free energy. Be able to interpret energy diagrams, calculate heat changes, and understand the factors that influence the spontaneity of reactions.

10. Periodic Table and Chemical Families

The periodic table organizes elements based on their properties. Study the trends in atomic size, ionization energy, electron affinity, and electronegativity across periods and groups. Familiarize yourself with the properties and characteristics of different chemical families, such as alkali metals, halogens, and noble gases.

Additional Resources and Practice Materials

To further enhance your preparation for the NECO Chemistry exam, consider utilizing additional resources and practice materials. Here are some recommendations:

• Online study platforms that offer interactive lessons, quizzes, and practice exams.
• Educational YouTube channels that provide video explanations of key chemistry concepts.
• Chemistry textbooks and study guides published by reputable authors and publishers.
• Past questions and answers from previous NECO Chemistry exams to familiarize yourself with the exam format and identify recurring topics.

Final Thoughts

Preparing for the NECO Chemistry Objective & Essay 2023 questions and answers requires dedication, perseverance, and a structured study plan. By following the strategies outlined in this guide and focusing on the key topics and concepts, you can significantly improve your chances of success in the exam. Remember to practice regularly, seek clarification when needed, and approach the exam with confidence. Good luck!

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NECO CHEMISTRY PRACTICAL 2023 Verified Essay and Objective Answers

Posted by Hedowho on 12 July, 2023

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NECO CHEMISTRY PRACTICAL Theory and Objective Answers (100%legit) CHEMISTRY PRACTICAL Essay verified Free  (Expo) for National Examination Council. NECO CHEMISTRY PRACTICAL Questions For you to have good NECO result in  CHEMISTRY PRACTICAL as well as repeated questions for free in this post.

NECO GCE June/July 2023 FREE CHEMISTRY PRACTICAL   QUESTION AND ANSWER ROOM 

(1a) [TABULATE]

Burette Reading (cm³) | Rough | Titration I | Titration II Final Reading (cm³) | 21.50 | 43.00 | 22.00 Initial Reading (cm³) | 0.00 | 21.50 | 00.00 Volume of A used (cm³) | 21.50 | 21.50 | 22.00

(1ai) Average Volume of acid used = 21.50 + 21.50/2 = 21.50cm³

(1aii) Solution B[Sodium trioxocarbonate (iv)] feels soapy

(1bi) Conc. B in mol/dm³ =? Ca= 0.04, Va= 21.50cm³, na= 1 Cb= ? , Vb= 25.00cm³ nb= 1

CaVa/CbVb = na/nb = 0.04×21.50/Cb×25.00 = 1/1 Cb= 0.04×21.50/25.00 = 0.86/25.00 Cb= 0.0344mol/dm³

(1bii) Conc. of B in g/dm³ = Conc. of B in mol/dm³ × molar mass of B

Molar mass of B(NaCO₃)= (23×2) + 12 + (16×3) = 106

:. Conc. of B in g/dm³ = 0.0344×106 = 3.6g/dm³

(1biii) 1 mole of Na₂Co₃ = 1mole of Na₂So₄

:. 0.0344 mole of Na₂Co₃ = 0.0344 mole of Na₂So₄ № of mole= mass/ molar mass

Molar mass of Na₂So₄= (23×2)+32+(16×4)=142 :. 0.0344 = mass/142 Mass=142×0.0344=4.9g

(1biv) 1 mole of Na₂Co₃= 1 mole of CO₂

0.0344 mole of Na₂Co₃ = 0.0344 mole of CO₂ :. № of mole = volume/ molar volume = 0.0344 = volume of CO₂/22400cm³ =771cm³ ========================================

(2ai) [TABULATE]

=TEST= C + heat

=OBSERVATION= Formation of yellow flame

=INFERENCE= Na⁺ present

(2aii) =TEST= C + distilled water + shake

=OBSERVATION= It readily dissolve in water

=INFERENCE= C is a soluble in water

(2aiii) =TEST= Solution C + litmus paper

=OBSERVATION= It changes moist red litmus to blue and no effect blue

=INFERENCE= Solution C is alkaline

(2bi) =TEST= 1st portion of solution C + barium chloride

=OBSERVATION= White precipitate formed

=INFERENCE= CO₃²⁻ , SO₄²⁻ , S²⁻ or SO₃²⁻

(2bii) =TEST= Add dilute HCl to product in (bi)

=OBSERVATION= White precipitate dissolved

=INFERENCE= CO₃ , SO₃²⁻ or S₃²⁻

(2biii) =TEST= To the second portion add phenolphthalein

=OBSERVATION= Purple colour observed

=INFERENCE= C is alkaline ========================================

(3ai) Sulphur (iv) oxide and hydrogen sulphide.

(3aii) Liberation of hydrogen gas with pop sound and formation of green iron (ii) chloride solution

(3aiii) Spatula, beaker, weighing balance, standard volumetric flask

(3bi) Solution turns red

(3bii) Turns from brown to green

(3biii) A colourless, odourless, acidic gas liberated which turns blue litmus paper red and turn lime water milky. ========================================

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2023 Neco Chemistry Essay and Objective Questions and Answers

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Chemistry-Obj USE THIS OBJ FOR A1.. FEW CORRECTION MADE 01-10: DEADADECAD 11-20: BAEDDBDBAE 21-30: CCDCADDECD 31-40: EBEEBEBCEE 41-50: BCCECEDADD 51-60: DABBDEAECA

CHEMISTRY-ANSWERS! (1ai) (i) Manufacturing sulfuric acid (ii) Vulcanization of rubber (iii) Formulation of Pesticides and fungicides (1aii) (i) It is a colorless gas that has a distinct smell of rotten eggs (ii) Hydrogen sulphide is soluble in water to some extent (1aiii) Soaps are made from natural products while detergents are made from synthetic products. (1aiv) Detergents is for household cleaning and laundry purposes (1bi) Number of neutrons = Mass number (A) – Atomic number (Z) I. ²³₁₁X A = 23 (mass number) Z = 11 (atomic number) Number of neutrons = 23 – 11 = 12 II. ³⁹₁₉Y A = 39 (mass number) Z = 19 (atomic number) Number of neutrons = 39 – 19 = 20 (1bii) Molar mass: Na = 22.99 g/mol O₂ = 2 * 16.00 g/mol = 32.00 g/mol Now, let’s calculate the mass of oxygen needed: First, calculate the number of moles of sodium (Na) in 9.2g: Number of moles = Mass / Molar mass Number of moles of Na = 9.2g / 22.99 g/mol ≈ 0.4002 mol Since the mole ratio of Na to O₂ is 4:1, the number of moles of O₂ needed is: Number of moles of O₂ = 0.4002 mol / 4 ≈ 0.1001 mol Now, calculate the mass of oxygen needed: Mass of O₂ = Number of moles of O₂ * Molar mass of O₂ Mass of O₂ = 0.1001 mol * 32.00 g/mol ≈ 3.204 g Therefore, approximately 3.204 grams of oxygen are needed to burn 9.2 grams of sodium. (1biii) CaCO₃(s) + 2 HCl(aq) —> CaCl₂(aq) + CO₂(g) + H₂O(l) From the balanced equation, 1 mole of calcium carbonate (CaCO₃) reacts with 2 moles of HCl to produce 1 mole of calcium chloride (CaCl₂). Molar masses: CaCO₃ = Ca(40.08) + C(12.01) + 3O(16.00) = 100.09 g/mol CaCl₂ = Ca(40.08) + 2Cl(35.45) = 110.98 g/mol Now, let’s calculate the number of moles of CaCO₃ in 50g: Number of moles of CaCO₃ = Mass / Molar mass Number of moles of CaCO₃ = 50g / 100.09 g/mol ≈ 0.4998 mol Since the mole ratio of CaCO₃ to CaCl₂ is 1:1, the number of moles of CaCl₂ that can be obtained is also approximately 0.4998 mol. Thus, about 0.4998 moles of calcium chloride can be obtained from 50g of limestone in the presence of excess hydrogen chloride.

(1ci) (i) Sol: A sol is a colloidal solution in which solid particles are dispersed in a liquid medium. (ii) Aerosol: An aerosol is a colloidal solution in which liquid or solid particles are dispersed in a gas medium. (1cii) The law of definite proportions, also known as the law of constant composition, states that a given chemical compound always contains its constituent elements in fixed and definite proportions by mass. This means that the ratio of the masses of the elements in a compound is constant, regardless of the compound’s origin or method of preparation. (1ciii) (I) Sodium trioxonitrate (V) is also known as sodium nitrate, with the chemical formula NaNO₃. The atomic masses are as follows: Na (Sodium) = 22.99 g/mol N (Nitrogen) = 14.01 g/mol O (Oxygen) = 16.00 g/mol Relative molecular mass of NaNO₃ = (1 * Na) + (1 * N) + (3 * O) Relative molecular mass of NaNO₃ = (1 * 22.99 g/mol) + (1 * 14.01 g/mol) + (3 * 16.00 g/mol) Relative molecular mass of NaNO₃ = 22.99 g/mol + 14.01 g/mol + 48.00 g/mol Relative molecular mass of NaNO₃ = 85.00 g/mol Therefore, the relative molecular mass of sodium nitrate (NaNO₃) is 85.00 g/mol. (II) Copper (II) trioxosulphate (VI) pentahydrate is also known as copper (II) sulfate pentahydrate, with the chemical formula CuSO₄ · 5H₂O. The atomic masses are as follows: Cu (Copper) = 63.55 g/mol S (Sulfur) = 32.06 g/mol O (Oxygen) = 16.00 g/mol H (Hydrogen) = 1.01 g/mol Relative molecular mass of CuSO₄ · 5H₂O = (1 * Cu) + (1 * S) + (4 * O) + (10 * H) + (5 * O) Relative molecular mass of CuSO₄ · 5H₂O = (1 * 63.55 g/mol) + (1 * 32.06 g/mol) + (4 * 16.00 g/mol) + (10 * 1.01 g/mol) + (5 * 16.00 g/mol) Relative molecular mass of CuSO₄ · 5H₂O = 63.55 g/mol + 32.06 g/mol + 64.00 g/mol + 10.10 g/mol + 80.00 g/mol Relative molecular mass of CuSO₄ · 5H₂O = 249.71 g/mol Therefore, the relative molecular mass of copper (II) sulfate pentahydrate (CuSO₄ · 5H₂O) is 249.71 g/mol.

(2ai) Mass of silver deposited (in grams) = (Current in Amperes × Time in seconds × Atomic mass of silver) / (1 Faraday)

Given: Current = 4.6 A Time = 90 minutes = 90 × 60 seconds = 5400 seconds Atomic mass of silver (Ag) = 108g/mol 1 Faraday = 96,500C Substituting the values to calculate the mass of silver deposited: Mass of silver deposited = (4.6 A × 5400 s × 108 g/mol) / 96,500 C Mass of silver deposited ≈ (2,682,720 g·s/mol) / 96,500 C Mass of silver deposited ≈ 27.8g

(2aii) (i) Electrode surface area (ii) Electrolyte temperature

(2aiii) (i) The oxidizing agent is MnO₄⁻(aq) (ii) The reducing agent is Fe²⁺(aq)

(2aiv) MnO₄⁻(aq) + 8H⁺(aq) + 5e⁻ —-> Mn²⁺ + 4H₂O(l)

(2bii) (i) Gases have no fixed shape or volume. (ii) Gases have low density compared to solids and liquids. (iii) Gases have high kinetic energy and are in constant motion.

(2biii) Faraday’s second law of electrolysis states that the mass of a substance deposited (or liberated) during electrolysis is directly proportional to the quantity of electric charge passed through the electrolyte.

(2biv) (i) Charcoal (ii) Coal

(2bv) Na (Sodium) > Ca (Calcium) > Mg (Magnesium) > Al (Aluminum)

(3ai) (i) Butan-2-ol – Secondary alkanol (ii) 2-methylpropanol – Primary alkanol (iii) 2-methylpropan-2-ol – Tertiary alkanol (3aii) (i) Fermentation (ii) Ethylene hydration (3aiii) Let the relative molecular mass of gas Z be M. (Rate of diffusion of hydrogen)/(Rate of diffusion of gas Z) = √(molar mass of gas Z)/√(molar mass of hydrogen) 6/1 = (√M)/(√2) 36 = M/2 M = 2×36 M = 72 (3bi) 1s², 2s², 2p⁴ (3bii) (i) It is a colorless (ii) It is soluble in water. (iii) It is tasteless (3biii) (i) Identify the longest chain. (ii) Name the substituents alphabetically (3biv) C₂H₄ + O₂ —> 2CO₂ + 2H₂O (3ci) Endothermic reaction can be defined as a form of heat reaction in which heat is absorbed from the surrounding into the reacting system. (3cii) Zn(s) + H₂SO₄(aq) —> ZnSO₄(aq) + H₂(g) (3ciii) Redox reaction. (3iv) (i) For refining petrol (ii) For food processing (iii) For producing fertilizer

(4ai) A super saturated solution is a solution that contains more than the maximum amount of solute that is capable of being dissolved at a given temperature. (4aii) 15/345 = Solubility *25/1000 Solubility =1000*15/25*345=15000/8625 Solubility = 1.79mol/dm³ (4aiii) (i) H₃0⁺ (ii) NH₄⁺ (iii) [CN]⁻₆ (4bi) (i) It has no chemical formula (ii) It can be separated physically (iii) Freezing air slowly yields different liquids at different temperatures (4bii) (i) Noble gases (ii) Carbon (iv) oxide (4biii) H₂SO₄ —-> 2H+ + SO₄²⁻ 1 mole of H₂SO₄ = 2 mole of H⁺ 0.1 mole of H₂SO₄ = 0.2 mole of H⁺ Mole = no. of H⁺/Avogadro’s constant No. of H⁺ = Mole * Avogadro’s constant = 0.2 * 6.0*10²³ = 1.2*10²³ ions (4biv) (i) Dative bonding (ii) Hydrogen bonding (4bv) (i) BRASS: Constituent: Copper and zinc. Use: Brass is used in the production of musical instruments decorative items and plumbing fixtures. (ii) BRONZE: Constituent: Copper and tin. Use: Bronze is used in the production of statues coins and various machinery.

(5ai) A base is a substance which when disolve produce hydroxyl ion (OH⁻) as the only negative ion

(5aii) (i) K₂O (ii) MgO

(5aiii) (i) it is used in printing inks and dyes (ii) it is used in making photographic chemicals

(5aiv) Aliphatic does not have good odour while an aromatic hydrocarbon has

(5av) M.m of XCl₃=10-8+(35-5*3) =10.8+106.5 =117.3 Vapour density =117.3/2=58.65

(5bi) (i) Temperature (ii) concentration (iii) surface area

(5bii) The law states that energy can neither be created nor destroyed in and isolated system.

(5biii) (i) burning of wood (ii) neutralization reaction

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NECO Chemistry Questions and Answers 2023 Objectives and Essay

• Post author: admin
• Post published: June 25, 2023
• Post category: NECO
• Post comments: 1 Comment

On this page, you’ll get NECO Chemistry 2023 answers. Have you been searching for an expo to help you pass NECO Chemistry  2023/2024, worry no more as we have all the answers to both objectives and essay and other exam details for NECO 2023?

You can now get NECO Chemistry objectives and essay answers on this page with ease. Please be guided that all the questions for NECO Chemistry have been proved here for free. Continue reading to see all the answers.

NECO Chemistry Questions and Answers 2023 Objective and Essay

You are welcome to the June/July 2023 Expo Runz Real and Verified NECO Chemistry (Obj and Essay/Theory) Questions and Answers.

All the NECO Chemistry questions have been carefully answered and will soon be uploaded to this page. If you really want to get all the answers at your fingertips then keep reading to find out what is demanded of you.

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If you’re still searching for answers to 2023 NECO Chemistry theory and OBJ questions then search no more, any moment from now our team will upload 2023 NECO Chemistry theory and OBJ answers for all interested students. See NECO Chemistry objective and essay questions and answers below.

NECO Chemistry Answers 2023 Objective and Theory

First, you need to understand the nature of which these exams are set. NECO Chemistry Questions and Answers 2023 Objective and Theory is administered by the National Examination Council (NECO) of Nigeria.

The National Examination Council (NECO) is an examination body in Nigeria that conducts the Senior Secondary Certificate Examination and the General Certificate in Education in June/July and November/December respectively.

For those asking for areas of specialization, just have it in mind that 2023 NECO Chemistry questions are set from the SS1 to SS3 Chemistry syllabus.

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NOTE:  There is nothing like NECO Chemistry Expo 2023 online. All students are advised to study hard and stop patronizing online fraudsters/vendors who claim to provide such services.

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NECO GCE 2023 Chemistry Objective & Theory Questions And Answers

December 5, 2023 Wakagist Neco 0

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Home » PAST QUESTIONS » 2023 NECO Chemistry Essay Questions and Answers For all Candidates

2023 NECO Chemistry Essay Questions and Answers For all Candidates

2023 Neco Chemistry Questions: If you are a candidate who is in search of Neco Agricultural Science Questions then you are on the right website because we try to make sure all our audience studies hard to pass with proper information.

If you need us to help you with more updated information at the right time about the 2023 Neco Chemistry Questions, kindly subscribe or bookmark our website for us to provide you with it.

Nkedugists understand how students feel whenever it comes to closing time for an external exam such as  Waec,   Neco , Jamb, and Post Utme, that is why we make sure any question we are releasing/publishing is always the best option questions you are to see in your exam day because we always follow scholars and examiners. below are what we taught about before publishing it, which are;

• NECO GCE Chemistry Questions Questions
• NECO Chemistry Questions Questions
• 2020/2021 NECO Chemistry Questions
• NECO Chemistry Questions
• GCE Chemistry Questions
• NECO Chemistry Questions
•  Chemistry Questions for GCE
• 2020 NECO Chemistry Questions
• 2022 Neco Chemistry Questions
• Neco Chemistry Questions 2022/2023

CHEMISTRY PAPER II Paper 2 will last for 1 hour 30 min Attempt two questions from this section

(1a) Ammonium chloride —> sublimation Ink —> chromatography Iron filling —> magnetic separation

(1aii) -Example Of physical Change (i)change of matter (ii)evaporation of sodium chloride

-Example of chemical change (i)burning of firewood (ii)rusting of iron

(1bi) (i)they are good reducing agent (ii)they form basic oxide (iii)they formed electro valent bonding

(1bii) Aluminum tetraoxosulphate(vi) is prepared by the action of hot concentrated tetraoxosulphate(vi)acid on aluminum oxide Al2O3(s) + 3H2SO4(aq)—->Al2(SO4)3(aq)+3H2O(i) Aluminum tetraoxosulphate(vi) is moderately soluble in water

(1ci) Hydrogen

(1cii) (i)it is denser than air (ii)it is very poisonous

(1ciii) Pb(NO3)2+H2S—->Pbs+2HNO3

(1civ) It turn black due to the formation of black lead (II) sulphide

(1di) Water gas contains flammable gases whereas the producer gas contains both flammable and non-flammable gases

(1dii) (I) Diamond —> Octahedral in shape (II) Graphite —> Hexagonal in shape

(1e) (i) For manufacturing of ammonia and fertilizer (ii) It is used as a refrigerant and also used to shrink metal parts (iii) It is used in grinding substances that are too tough to grind at normal temperature

(2aii) Avogadro’s law states that equal volumes of all gases under the same temperature and pressure contain the same number of molecules

(2aii) Given : 2SO2(aq) + O2(g) –> 2SO3(aq)

The volume of oxygen, O2 required = 1/2*7.50dm³ =3.75dm³

No of moles required = 3.75/22.4moles =0.1674moles

No of oxygen molecules required = 0.1674×6.02×10^23 =1.008×10^23molecules

(2bi) (I) NaCl —–> Valency of chlorine is 1 (II) NaO2 —–> Valency of oxygen is 2 (III) Na3N ——> Valency of Nitrogen is 3

(2bii) (i)Formation of black soap (ii)Formation of glycerol (iii)It helps in the precipitation of large biomolecules such as protein

(2ci) (i)Na2O (ii)MgO (iii)CaO

(2cii) Because they react with water to form acids

(2ciii) – Reaction with sulphur S(s) + O2(g) —> SO2(g)

– Reaction with metals 4Na(s) + O2(g) —-> 2NaO(s)

(2di) Ion is any atom or group of atoms which possess an electric charge

(2dii) TABULATE PLS ION : H^+, F^-, N^3+

NUMBER OF PROTONS: 1,9,13

NUMBER OF NEUTRONS : 0, 10, 14

NUMBER OF ELECTRONS : 0, 10, 10

(2ei) Monosaccharides are simple six-carbon sugar having the formula C6H12O6 eg glucose and its isomers are fructose and galactose, both obtainable from fruits and honey

(2eii) (i)fructose (ii)galactose

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Thanks for the update

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